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maksim [4K]
2 years ago
13

What is the slope of the line graphed below?

Mathematics
2 answers:
lukranit [14]2 years ago
6 0
The answer is 5
Remember slope is rise/run which is 5/1
Otrada [13]2 years ago
3 0

Answer:

B. 1/5

Step-by-step explanation:

Start at point (1,-2)

Then, go right 1 and up 5 to reach point (2,3)

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What is the first step to solve the absolute value equation 2|x+5|=16 for x?
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Isolate the absolute value expression
4 0
3 years ago
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53w+13<56w+16 I need help.​
Alborosie

Answer:

w>(-1)

Step-by-step explanation:

Answer on a number line is open circle at -1 all the way to positive 8

7 0
3 years ago
Jacob’s recipe calls for 4 7/8 cups of raisins. He has 6/11 of the amount that he needs.
boyakko [2]
If you would like to know how many cups of raisins does Jacob have, you can calculate this using the following steps:

6/11 ... 1/2
4 7/8 cups ... 5 cups

1/2 of 5 cups = 1/2 * 5 = 5/2 = 2 1/2 cups

The correct result would be C. 2 1/2.
8 0
3 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
If −5e^x^2 y=x and y(−5)=0, find y′(−5) by implicit differentiation
xenn [34]
Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5
6 0
2 years ago
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