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Dahasolnce [82]
3 years ago
11

Picture attached please help i will give brainliest answer

Mathematics
2 answers:
kakasveta [241]3 years ago
6 0
I believe it is D. Just ignore the 3 then subtract 2/7 from the 4/7, which is 2/7. Now put the 3 back and you'll have 3 4/7.
mash [69]3 years ago
4 0
To answer, you first have to convert the mixed number, 3 4/7, into an improper fraction. You do this by multiplying 3 by 7 and then adding 4, which is 25/7. Now you can do 25 - 2 = 23/7. 23 ÷ 7 = 3 2/7, which is your answer. (D)
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Enter the<br> value of p so that the expression<br> 3(n + 5) is equlvalent to (n + p)3
MA_775_DIABLO [31]

Answer:

p=5

Step-by-step explanation:

a(x+y) is also (x+y)a

So if 3(n+5) has to be equivalent to (n+p)3, then p has to be 5.

---

hope it helps

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3 years ago
Saul has 8 bags. He records the weight of each bag on the line plot.
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24

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just MultiplMultiply 8 times 3 and 24

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If you roll a six-sided dice, what is the probability of rolling an odd number?
fomenos

Step-by-step explanation:

A six sided dice contains even numbers on three sides and odd numbers on remaining three sides.

Therefore,

Probability of rolling an odd number

=  \frac{3}{6}  \\ \\   =  \frac{1}{2}

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3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
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