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Dahasolnce [82]
3 years ago
11

Picture attached please help i will give brainliest answer

Mathematics
2 answers:
kakasveta [241]3 years ago
6 0
I believe it is D. Just ignore the 3 then subtract 2/7 from the 4/7, which is 2/7. Now put the 3 back and you'll have 3 4/7.
mash [69]3 years ago
4 0
To answer, you first have to convert the mixed number, 3 4/7, into an improper fraction. You do this by multiplying 3 by 7 and then adding 4, which is 25/7. Now you can do 25 - 2 = 23/7. 23 ÷ 7 = 3 2/7, which is your answer. (D)
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Write an equation for the following: y varies directly with x and z. Find K when x=2, y=12 and z=5.
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\qquad \qquad \textit{direct joint variation} \\\\ \textit{\underline{y} varies directly with \underline{x} and \underline{z}}~\hspace{8.5em} \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}xz~\hfill } \\\\ \textit{\underline{y} varies directly with \underline{x}, }w^2\textit{ and }z^5~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}xw^2z^5~\hfill } \\\\[-0.35em] ~\dotfill

y = kxz\qquad \textit{we know that} \begin{cases} x=2\\ y=12\\ z=5 \end{cases}\implies 12=k(2)(5) \\\\\\ \cfrac{12}{(2)(5)}=k\implies \cfrac{6}{5}=k~\hspace{10em}\boxed{y=\cfrac{6}{5}xz}

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Answer:

The function is increasing from x = 0 to x = 1.

Step-by-step explanation:

A <u>function</u> is increasing when the <u>y-value increases</u> as the <u>x-value increases</u>.

A <u>function</u> is decreasing when the <u>y-value decreases</u> as the <u>x-value increases</u>.

From x = -2 to x = -1 the function is decreasing as the y-value decreases as the x-value increases:  

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From x = -1 to x = 0 the function is increasing as the y-value increases as the x-value increase:  

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From x = 0 to x = 1 the function is increasing as the y-value increases as the x-value increase:  

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