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3 years ago

10

Which term best describes the expression? 6gh^2 - 4g^2h + g

1 answer:

kati45 [8]3 years ago

4 0

4. not a polynomial because you have 4g raised to "2h" which in order for it to be polynomial it has to be a number or constant.

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You scored the following grades on your first three math tests: 71, 78, 81. You only have one test remaining. What is the highes

gulaghasi [49]

Assuming the highest score for a test is 100.

Highest possible total scores for 4 tests = 71 + 78 + 81 + 100 = 330

Highest possible average score for 4 tests = 330 ÷ 4 = 82.5

Answer: 82.5

8 0

3 years ago

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Solve dy/dx + y/x square = 1/x square

Yanka [14]

Answer:

See below.

Step-by-step explanation:

$\frac{dy}{dx}+\frac{y}{x^2}=\frac{1}{x^2}\\\\\frac{dy}{dx}=\frac{1}{x^2}-\frac{y}{x^2}\\\\\frac{dy}{dx}=\frac{1-y}{x^2}$

The first step could be more complicated if the fractions didn't already have a common denominator.

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3 years ago

2(3x+1)+2x=8x+1<br><br> Help I don’t get this. I will give points if wanted

geniusboy [140]

Answer:

2(3x+,1)+2x=8x+1

=6x+2+2x=8x+1

=8x+2=8x+1

=2-1=8x-8x

=1=x

So x=1

7 0

3 years ago

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You are testing the claim that the proportion of men who own cats is smaller than the proportion of women who own cats. You samp

MariettaO [177]

Answer:

Given:You sample 160 men, and 25% own cats

You sample 120 women, and 20% own cats.

To Find : Find the test statistic, rounded to two decimal places.

Solution:

You sample 160 men, and 25% own cats.

No. of men have cats = $\frac{25}{100} \times 160$

= $40$

So, $n_1=160 , y_1=40$

You sample 120 women, and 20% own cats.

No. of women have cats = $\frac{20}{100} \times 120$

= $24$

So, $n_2=120 , y_2=24$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{40}{160}$

$\widehat{p_1}=0.25$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{24}{120}$

$\widehat{p_2}=0.2$

Let $p_1$ and $p_2$ be the probabilities of men having cat and women having cat receptively

$H_0:p_1=p_2\\H_a:p_1$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{24+40}{160+120}=0.228$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.25-0.2}{\sqrt{0.228(1-0.228)(\frac{1}{160}+\frac{1}{120})}}$

test statistic : $0.986$

So, test statistic is 0.986

8 0

4 years ago

Math question<br><br><br><br> I have 3 for you

Reptile [31]

#1-answer c
#2-answer b
#3-answer a

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3 years ago

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