Answer:
a) 5units
b) (4.5, 4)
Step-by-step explanation:
Let the coordinate of P and Q be P(3, 2) and Q(6, 6)
PQ can be gotten using the distance formula;
PQ =√(6-2)²+(6-3)²
PQ = √4²+3²
PQ =√16+9
PQ =√25
PQ = 5units
Midpoint M is expressed as;
M(X, Y) = {(x1+x2)/2, y1+y2/2}
X = x1+x2/2
X = 3+6/2
X= 9/2
X = 4.5
Similarly;
Y = y1+y2/2
Y = 2+6/2
Y = 8/2
Y = 4
Hence the midpoint of PQ is (4.5, 4)
Simplifying
f + -6 = 3f + 1
Reorder the terms:
-6 + f = 3f + 1
Reorder the terms:
-6 + f = 1 + 3f
Solving
-6 + f = 1 + 3f
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Add '-3f' to each side of the equation.
-6 + f + -3f = 1 + 3f + -3f
Combine like terms: f + -3f = -2f
-6 + -2f = 1 + 3f + -3f
Combine like terms: 3f + -3f = 0
-6 + -2f = 1 + 0
-6 + -2f = 1
Add '6' to each side of the equation.
-6 + 6 + -2f = 1 + 6
Combine like terms: -6 + 6 = 0
0 + -2f = 1 + 6
-2f = 1 + 6
Combine like terms: 1 + 6 = 7
-2f = 7
Divide each side by '-2'.
f = -3.5
Simplifying
f = -3.5
A constant in the equation of a curve that can be varie
M-30=10
It could also be 30-m=10
The answer for the first one would be 10+30=m
m=40
The answer for the second one would be 30-10=m
m=20
Hope this helps :)
