3 years ago

I need help with this plsss

1 answer:

4 0

Answer:

what's the question? u did not said it

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Fofino [41]

The probability of senior citizens suffer from sleep disorders is

$P(A)=0.91$

The probability of senior citizens suffer from anxiety is,0.09.

$P(B)=0.09$

The probability of seniors suffer from both sleep disorders and anxiety is,

$P(A\cap B)=0.06$

a. The probability that a senior citizen suffers from anxiety, given that he or she has a

sleep disorder.

$P(A|B)=\frac{P(A\cap B)}{P(B)}$ $P(A|B)=\frac{0.06}{0.09}$ $P(A|B)=0.67$

8 0

2 years ago

olga nikolaevna [1]

34+56=90 this is your answer

Hope this helps lol

4 0

3 years ago

Alex

I’m sorry I don’t know

3 0

3 years ago

yanalaym [24]

Answer:

55,050

Step-by-step explanation:

7 0

4 years ago

GREYUIT [131]

I think 104,000 is the answer because when 26,000 is double it's 52,000 so I doubled 52,000 and 104,000 is what I got.

5 0

3 years ago