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lukranit [14]
3 years ago
5

I need help with this plsss

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

what's the question? u did not said it

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The answer is below

Step-by-step explanation:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\for\ a \ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\where\ x=raw\ score,\mu=mean, \sigma=standard deviation

Given that n = 49, μ = 260 mg/dL, σ = 35 mg/dL

a) For x < 210:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{210-260}{35/\sqrt{49} } =-10

From the normal distribution table, P(x < 210) = P(z < -10) = 0.0001

b) For x > 205:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{205-260}{35/\sqrt{49} } =-11

For x < 215:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{215-260}{35/\sqrt{49} } =-9

P(205 < x < 215) = P(-11 < z < -9) = P(z < -9) - P(z < -11) = 0.0001 - 0.00001 = 0.00009

c) For x < 200:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{200-260}{35/\sqrt{49} } =-12

From the normal distribution table, P(x < 200) = P(z < -12) = 0.00001

d) For x > 222:

z=\frac{x-\mu}{\sigma/\sqrt{n} } =\frac{222-260}{35/\sqrt{49} } =-7.6

From the normal distribution table, P(x > 200) = 1 - P(z < -12) = 1 - 0.0001 = 0.9999

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