It is multiplying polynomials

(x+2)^2 - (y+3)^2 factories this. Pls help me .

alekssr [168]

Answer:x^2−y^2+4x−6y−5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

HELP ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️WILL MARK BRAINLYEST‼️‼️‼️

Rainbow [258]

Answer:

8 one-dollar bills

3 five-dollar bills

2 ten-dollar bills

Step-by-step explanation:

Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13

x + 5y + 10z = 43

x = 4z

x + y + z = 13

x + 5y + 10z = 43

x + 0y - 4z = 0

x + y + z = 13

5y + 14z = 43

-y - 5z = -13

5y + 14z = 43

-5y - 25z = -65

-11z = -22

z = 2

x = 4z

x = 4*2 = 8

x + y + z = 13

8 + y + 2 = 13

10 + y = 13

y = 3

3 0

2 years ago

Haley makes earrings and packages them into cube boxes that measure 1/6 foot wide. how many 1/6 foot cubic boxes can she fit int

navik [9.2K]

Answer: $28\ cubes$

Step-by-step explanation:

The volume of a cube can be found with this formula:

$V_{(c)}=s^3$

Where "s" is the lenght of any edge of the cube.

The formula for calculate the volume of a rectangular prism is:

$V_{rp}=lwh$

Where "l" is the lenght, "w" is the width and "h" is the height.

We need to find the volume of a cube box:

$V_1=s^3=(\frac{1}{6}ft)^3=\frac{1}{216}ft^3$

To find the volume of the shipping box, first we must convert the mixed number to an improper fraction:

$1\frac{1}{6}=\frac{(6*1)+1}{6}=\frac{7}{6}$

Then the volume of the shipping box is:

$V_2=lwh\\\\V_2=(\frac{7}{6}ft)(\frac{1}{3}ft)(\frac{1}{3}ft)=\frac{7}{54}ft^3$

Now, in order to find the number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:

$\frac{\frac{7}{54}ft^3}{\frac{1}{216}ft^3}=28$

6 0

3 years ago

Joaquín compró una docena y media de factura la docena son parte de grasa dos tercios tiene dulce de leche y el resto son medial

Juli2301 [7.4K]

Answer:

2 facturas de grasa.

12 facturas con dulce de leche

4 medialunas

Step-by-step explanation:

Una docena contiene 12 facturas y media docena contiene 6 facturas. Entonces Joaquin compro un total de 18 facturas (12+6). Si la novena parte (1/9) de las facturas son de grasa entonces solo multiplicamos esta fraccion por la totalidad de las facturas.

18 * (1/9) = 2 facturas de grasa.

La cantidad de facturas que tienen dulce de leche son dos tercios (2/3) de la totalidad. Entonces multiplicamos esta fracion for la totalidad.

18 * (2/3) = 12 facturas con dulce de leche

Por final, la cantidad de media lunas es el resto de las facturas, entonces descontamos las facturas de grasa y con dulce de leche de la totalidad para saber cuantas facturas son medialunas

18 - 2 - 12 = 4 medialunas

8 0

3 years ago

The thickness of glass sheets produced by a certain process are normally distributed with a mean of μ = 3.50 millimeters and a s

Lina20 [59]

Answer:

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Step-by-step explanation: omg fydvrhuguysegegg7e8se is actdgyhuy ting syfdpuo cjzivs8r8hhy9ahesyehu8y7es8eseyhues

6 0

3 years ago