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Afina-wow [57]
3 years ago
13

Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis.

If point H is located at (-2, 0), what are the coordinates of H′ ?
Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0
Since it is stretched vertically, the transformation is
(x,y) -> (x, ky)   where k is the vertical scale factor = 2.5

If H(-2,0), then H' = (-2,0)->(-2,2.5*0)=(-2,0)
BaLLatris [955]3 years ago
6 0

Answer:

Step-by-step explanation:

Alright, lets get started.

The square is stretched vertically.

The scale factor is given as 2.5 = k

The point H is changes to H'

The given H is  : (-2, 0)

The new stretched H' will be : (-2, k *0)

because k is the scale factor

So, new H' point will be : (-2, 2.5*0) = (-2, 0)

means the co-ordinates of H' is (-2,0)   :   Answer

Hope it will help :)

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