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mart [117]
3 years ago
12

The thickness of glass sheets produced by a certain process are normally distributed with a mean of μ = 3.50 millimeters and a s

tandard deviation of σ = 0.11 millimeters. What is the value of c for which there is a 99% probability that a glass sheet has a thickness within the interval?
Mathematics
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

ok dhufybggoe7sggeu8r7e

Step-by-step explanation: omg fydvrhuguysegegg7e8se is actdgyhuy ting syfdpuo cjzivs8r8hhy9ahesyehu8y7es8eseyhues

You might be interested in
4. Break-Even Analysis
DiKsa [7]

Answer:

x = 1178 games

Step-by-step explanation:

Let the number of games = x

Let the total cost = Tc

Let the total revenue = Tr

Given the following data;

Investment = $10,000

Cost of each game = $1.50

Selling cost = $9.99

Total cost, Tc = (Cost of each game * Number of games) + Investment

Tc = 1.50x + 10000

Total revenue, Tr = Selling cost * Number of games

Tr = 9.99x

Breakeven point is when total cost is equal to total revenue;

Tc = Tr

1.50x + 10000 = 9.99x

9.99x - 1.50x = 10000

8.49x = 10000

x = \frac {10000}{8.49}

x = 1177.86 ≈ 1178 games.

<em>Therefore, the number of games that must be sold before the business breaks even is 1178 games. </em>

4 0
3 years ago
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
Read 2 more answers
Someone please HELPP me
Mazyrski [523]

Answer:

32 remaining cups for Kin

Step-by-step explanation:

7 0
3 years ago
tara bakes 225 cookies in 5 hours, and she uses 8 pounds of sugar. she divide 225 by 5 to grt a rate of 45. which of the followi
Sati [7]

Options :

A cookies per pound

B. O pounds per hour

c. cookies per hour

D. hours per cookie

Answer: C.) Cookies per hour

Step-by-step explanation:

Given the following :

Number of cookies baked = 225 cookies

Total time taken = 5 hours

Amount of sugar used = 8 pounds

Tara divides 225 by 5; 225 / 5 = 45

Rate gives the amount or number of times something occurs within a given period, Hence

The rate obtained by Tara corresponds to the ratio of ; (Total cookies baked / total time taken) = (225 / 5), this translates to the amount or number of cookies baked within an hour.

6 0
3 years ago
Please help me with this someone
zepelin [54]

Answer: The best estimate for this is 52.

3 0
3 years ago
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