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3 years ago

If the height of the cylinder is 3 inches, what is the volume of the cylinder? Write your answer in terms of p.

Mathematics

2 answers:

azamat3 years ago

7 0

Formula for Volume of Cylinder you need the radius

Harrizon [31]3 years ago

4 0

Answer:

if the radius is 5 inches we simply find the area first

pi x r^2 (squared)

3.4 x 5 x 5

a = 34cm^2

v = a x h

= 34 x 3inch

=102inch^3

Replace p values as pi

as pi is 3.4 102/3.4 =30

To look like this

30px= 34x * 3x - x

102x -x = 30px

we use and rid of parenthesis

102x=30p

30/102x = 3.14p

x=3.14p

Step-by-step explanation:

You will see the cylinder is a fraction length of 0.5 so we just divide by 10 if using 0.5 inches.

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Suppose you waited 10 years to invest in the same retirement fund and have the same $400,000 for retirement at the same 8% inter

Ierofanga [76]

Answer:

Step-by-step explanation:

Using the compound interest formula to fins the amount after 10years;

A = P(1+r)^n

Principal P = $400,000

Rate r = 8% = 0.08

Time t = 10 years

Substitute

A = 400,000(1+0.08)^10

A = 400,000(1.08)^10

A = 400,000(2.1589)

A = 863,569.99

A ≈ 863,570

Hence the amount after 10 years is $863,570

Monthly deposit = $863,570/120 (10 years is equivalent to 120months)

Monthly deposit = 7,196.42

<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>

7 0

3 years ago

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

Speed of boat in still water $=14\ ms^-1$

Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

3 0

3 years ago

If a car travels at a speed of 25 mi/h for t hours, then travels 45 mi/h for m hours. What does the expression 25t + 45m represe

dlinn [17]

The expression of 25t +45m shows the total number of miles driven at both speeds. In order to solve this equation you would need to know the total number of hours driven in order to multiply that by the appropriate speed in terms of miles per hour.

6 0

3 years ago

PLeAsE sEnD hElP !!!!!!!!!!!!!!!!

Luba_88 [7]

Answer:

5 units

Step-by-step explanation:

If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and

BG = AG = CG as radii of the circumcirle.

Consider right triangle BEG. By the Pythagorean theorem,

$BG^2=EG^2+BE^2\\ \\BG^2=4^2+3^2\\ \\BG^2 =16+9\\ \\BG^2=25\\ \\BG=5\ units$

This gives us that

AG = BG = 5 units

3 0

3 years ago

1. Nasim thinks of a number.

mrs_skeptik [129]

Step-by-step explanation:

5x-16 = 3 (10+x)

=> x= 23

7 0

2 years ago