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Svetradugi [14.3K]
3 years ago
4

Which condition will create an overlap at a vertex of polygons?

Mathematics
2 answers:
stira [4]3 years ago
4 0

Answer:

Option c.

Step-by-step explanation:

A polygon is a simple closed curve. If a convex polygon has n sides, the sum of its interior angles is equal to (n-2)180^{\circ}.

The sum of exterior angles of any polygon is equal to 360^{\circ}.

However, overlap will be created at a vertex of polygons if the sum of the measures of the angles is greater than 360 degrees.

So, option c. is correct.

GuDViN [60]3 years ago
3 0
Hello there.

<span>Which condition will create an overlap at a vertex of polygons?

</span><span>c) The sum of the measures of the angles is greater than 360 degrees</span>
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v = 3 , 3/5

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5 {v}^{2}  - 18v + 9 = 0 \\ 5 {v}^{2}  - 3v - 15v + 9 = 0 \\ v(5v - 3) - 3(5v - 3) = 0 \\ (5v - 3)(v - 3) = 0 \\ v = 3 \\ v =  \frac{3}{5}

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3. Samantha earns $7.80 per hour. If her regular hours are 40
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An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

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