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bagirrra123 [75]
3 years ago
10

For what value of a does the equation ax^2−3x−5=0 have 1 as one of its roots?

Mathematics
1 answer:
allsm [11]3 years ago
5 0
Answer: When a = 8, one of the roots of the equation will be 1.

To solve this problem, you could graph the equation with a 1 in the place of the a on a graphing calculator (there are some online).

Then, just keep changing the a value until the graph crosses the x-axis at 1. When, you enter an a value of 8, it will have a root of 1.
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lab scale known to have a standard deviation of 0.001gram, speimen weghtted 8 times. average weiht is 4.1602 gram. what is 99% c
gtnhenbr [62]

Answer:

99\% CI=4.1602 \pm 0.0009

Step-by-step explanation:

From the question we are told that:

Sample size n=8

Mean \=x=4.1602

Standard deviation \sigma=0.001gram

Generally 99\% confidence from table  is mathematically given by

 99\% CI=4.1602 \pm *2.576*\frac{0.001}{\sqrt{{8}}}

 P(-z

 Z_{\alpha/2}=2.576

Generally the equation for 99\% confidence level (CI)  is mathematically given by

 99\% CI=\=x \pm Z_{\alpha/2*\frac{\sigma}{\sqrt{{n}}}

 99\% CI=4.1602 \pm 0.0009

5 0
3 years ago
32 + (-2) -2 please help
alex41 [277]

Answer:

28

Step-by-step explanation:

4 0
2 years ago
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Please help I cant fuigure this outtttttttttttttttttttttttttttttttttt
krek1111 [17]

Answer:

18 ft. By 13 ft.

Step-by-step explanation:

8 0
3 years ago
-2w(w+8) what is the answer
Julli [10]
-2w (w + 8)
 Assuming that it is a polynomial from which you must find the roots, we must first rewrite it:
 -2w (w + 8) = 0
 The roots are then:
 w1 = 0
 w2 = -8
 Assuming you only have to rewrite the expression, the answer is:
 -2w ^ 2 -16w
 Answer:
 w1 = 0 
 w2 = -8
 -2w ^ 2 -16w
5 0
3 years ago
What is the set of all solutions to the equation \sqrt{x + 2}= {-x} x+2 ​ =−xsquare root of, x, plus, 2, end square root, equals
NARA [144]

Answer:

x = 2 or x = -1

Step-by-step explanation:

Given

\sqrt{x + 2}= {-x}

Required

Find the possible values fo x

\sqrt{x + 2}= {-x}

Square both sides

( \sqrt{x + 2})^2= ({-x})^2

x + 2 = x^2

Equate to 0

x^2 - x - 2 = 0

Expand

x^2 + x -2x - 2 = 0

Factorize:

x(x + 1) - 2(x + 1) = 0

(x -2)(x +1) = 0

Split:

x - 2 = 0 or x + 1 = 0

x = 2 + 0 or x = 0-1

x = 2 or x = -1

3 0
2 years ago
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