Sorry if this is wrong and it doesn't hep but I got 32
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Area = r^2 x PI
to find r take the square root of the area:
r = √100 = 10
The circumference of a circle is the diameter times PI.
The diameter is 2 times r = 2 x 10 = 20
The circumference = 20PI m
The answer is C.
For every integer k from 1 to 10, inclusive the kth term of a certain sequence is given by [(−1)^(k+1)]∗[1/2^(k)].
If T is the sum of the first 10 terms in the sequence, then T is:
B.
A. Greater than 2
B. Between 1 and 2
C. Between 1/2 and 1
D. Between 1/4 and 1/2
E. Less than 1/4
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Answer:
x^2/1024 -y^2/7744 = 1
Step-by-step explanation:
The parent hyperbola relation is ...
x^2 -y^2 = 1
This has asymptotes of y = ±x and x-intercepts of ±1.
For the given hyperbola, we want to scale x by a factor of 32, and y by a factor that is 2.75 times that, or 88. Then the equation could be written as ...
(x/32)^2 -(y/88)^2 = 1
More conventionally, the denominator is shown at full value:
x^2/1024 -y^2/7744 = 1