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Fantom [35]
3 years ago
10

A sports stadium holds 14,600 people. There are eight home games in

Mathematics
2 answers:
frosja888 [35]3 years ago
8 0

Answer:

116800

Step-by-step explanation:

14600x8

166800

tia_tia [17]3 years ago
4 0

Answer:

b

Step-by-step explanation:

hope this helps you

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The amount of money,y, in cash box after x tickets are purchased for carnival games. The slope of the line is 1/4 and the y-inte
victus00 [196]

Amount of money received when x tickets are sold=$Y

Number of tickets sold=X

Slope of line= \frac{1}{4}

And , y- intercept = 8

Equation of line having slope m and y-intercept c is given by,

  y = m x + c,

Expressing the above statement in terms of linear equation in two variable i.e a line is

  Y = \frac{1}{4}X + 8

5 0
3 years ago
Factor completely x^3 + 1/8
maksim [4K]

Answer:

((2 x + 1) (4 x^2 - 2 x + 1))/8

Step-by-step explanation:

Factor the following:

x^3 + 1/8

Put each term in x^3 + 1/8 over the common denominator 8: x^3 + 1/8 = (8 x^3)/8 + 1/8:

(8 x^3)/8 + 1/8

(8 x^3)/8 + 1/8 = (8 x^3 + 1)/8:

(8 x^3 + 1)/8

8 x^3 + 1 = (2 x)^3 + 1^3:

((2 x)^3 + 1^3)/8

Factor the sum of two cubes. (2 x)^3 + 1^3 = (2 x + 1) ((2 x)^2 - 2 x + 1^2):

((2 x + 1) ((2 x)^2 - 2 x + 1^2))/8

1^2 = 1:

((2 x + 1) ((2 x)^2 - 2 x + 1))/8

Multiply each exponent in 2 x by 2:

((2 x + 1) (2^2 x^2 - 2 x + 1))/8

2^2 = 4:

Answer:  ((2 x + 1) (4 x^2 - 2 x + 1))/8

5 0
3 years ago
Read 2 more answers
there are about 1.5 grams of fat in 1 tabespoon of humus.how many grams of fat are in 2 1/2 cups of hummus ?
Kipish [7]
We'll first we need to know the in 1 cup there is 16 tablespoon.
so we could multiply  we need 2 1/2 cup so that is 16 (1cup) + 16 (1cup) +8 (1/2 cup)= 40 tablespoons... and 1 tablespoon is 1.5 grams of fat then we multiply 40 times 1.5 .... This is equal to 60 grams fat
So there is 60 grams of fat in 2 1/5 cups of hummus.
6 0
3 years ago
A motorist left town X at 08 00 for town Y situated 120km away, travelling at a constant speed of v km/hr, so as to arrive at Y
mote1985 [20]
<span>v = 45 km/hr u = 72 km/hr Can't sketch the graph, but can describe it. The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are 1. A segment from (0,0) to (80,60) 2. A segment from (80,60) to (110,60) 3. A segment from (110,60) to (160,120) The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed. 120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that. 45 * 4/3 = 180/3 = 60 km. So we have a good cross check that our initial speed was correct. v = 45 km/hr Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time: 60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr So the 2nd leg of the trip was at a speed of 72 km/hr</span>
6 0
3 years ago
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What is the surface area of the regular pyramid given below?
Liula [17]
I think if I had to guess the answer should be D 140
8 0
3 years ago
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