Answer:
13y= x + 59
Step-by-step explanation:
gradient= y² - y¹ / x²- x¹
=5 - 4 / 6- -7
= 1/ 13
<h3>equation of line:
<u>y=mx+c</u></h3>
x y
point (6,5)
<u>substitute</u>:
5= <u> </u><u>1</u><u> </u> (6) + c
13
c = 5 -<u> </u><u>6</u><u> </u>
13
= <u>5</u><u>9</u>
13
y=mx+c
13y= 1x + 59
1200/8 = x/3
150 = x/3
150 * 3 = x
450 = x
450 calories
-5+-12 is -17
For lack of a better metaphor, it's like digging a pit deeper than it already is.
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Answer:
12x -y = -87
Step-by-step explanation:
You can start with the 2-point form of the equation of a line and manipulate it to give you the standard form.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (-9 -3)/(-8 -(-7))(x -(-7)) +3
y = (-12/-1)(x +7) +3
y = 12x +84 +3
-12x +y = 87 . . . . . subtract the x-term
12x -y = -87 . . . . . . make the leading coefficient positive (per standard form)