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Svetllana [295]
3 years ago
13

 A rubber ball is dropped onto a hard surface from a height of 8 feet, and it bounces up and down. At each bounce it rises to 90

% of the height from which it fell.
a. Find a formula for h(n), the height in inches reached by the ball on bounce n.
h(n)=?
b. How high will the ball bounce on the 14th bounce? (in inches)
c. How many bounces before the ball rises no higher than an inch? 
Mathematics
1 answer:
Setler [38]3 years ago
7 0
A. 8 feet * 0.9 = distance after first bounce
h(n) = 8 * 0.9^n

b. 8 * 0.9^14 = 1.83 feet to 2 d.p.
1.83 * 12 = 21.96 inches

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It cost $36.75 for three tickets to visit the science center. It cost $51 for 4 tickets to visit the zoo. Which attraction will
Ber [7]
Find the cost for one ticket for the science center.
36.75 ÷ 3 = 12.25
Multiply the product with 12 to get the cost of 12 tickets.
12.25 × 12 = 147
Find the cost of 1 zoo ticket.
51 ÷ 4 = 12.75
Find the cost of 12 tickets by multiplying the product and 12
12.75 × 12 = $153
12 Science Center Tickets cost $147
12 zoo tickets cost $153

The Zoo costs more than the Science Center.

To find out how much more the Zoo costed, subtract 147 from 153.
153 - 147 = 6
The zoo only costs $6 more for 12 students.
So, you're answers are Zoo and $6
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Step-by-step explanation:

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schepotkina [342]

Answer:

3.56 cm.

Step-by-step explanation:

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h = 98 / (1/3 π (5.13)^2)

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Simplify without the absolute value |x+3| ; if x&gt;2
inna [77]

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

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x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

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