Answer:
3/1
Step-by-step explanation:
Answer:
37. {-1, -1}.
Step-by-step explanation:
I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.
x1 - x2 = 0
3x1 - 2x2 = -1
We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated
So the first equation becomes:
-2x1 + 2x2 = 0 Bring down the second equation:
3x1 - 2x2 = -1 Now adding, we get:
x1 + 0 = -1
so x1 = -1.
Now we substitute this value of x1 in the original first equation:
-1 - x2 = 0
-1 = x2
x2 = -1.
So the solution set is {-1, -1}.
If there are more than 2 equations you can use a combination of substitutions and eliminations.
what is the domain of the function: {(1, 3); (3, 5); (5, 7); (7, 9)}? a. {1, 3, 5, 7, 9} b. {1, 3, 5, 7} c. {1, 9} d. {3, 5, 7,
Papessa [141]
B. 1, 3, 5, and 7 are x values. Domain is the x value.
Answer:
L = 18 and w = 16
Step-by-step explanation:
The area of a rectangle is found by A = l*w. Since the length here is 2 more than the width or 2 + w and the width is w, substitute these values and A = 288 to solve for w.
To solve for w, move 288 to the other side by subtraction. Then factor and solve.
Set each factor equal to 0 and solve.
w - 16 = 0 so w = 16
w + 18 = 0 so w = -18
Since w is a side length and length/distance cannot be negative, then w = 16 is the width of the rectangle.
This means the length is 16 + 2 = 18.
