Answer:
The possible dimensions of the deck can be anything that adds up to be 130 m.
Step-by-step explanation:
<em>The perimeter could be 1m x 64m.</em>
Two sides would be 1m each (so 2m total) and the other two sides would be 64m each (128m total). 2 + 128 = 130m.
<em>The perimeter could be 15m x 50m.</em>
Two sides would be 15m each (so 30m total) and the other two sides would be 50m each (100m total). 30 + 100 = 130m.
You have to subtract the 6 first and then divide the rest by 1/8.
34-6=28
28×1/8=224
D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:

<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E

therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>
Answer:
B. -t+8
Step-by-step explanation:
add t to -2t and add 3 and 5
56*(4+15/60)
56*(240+15)/60
56*(255)/60
238 miles