This is how dora subtracts 73-26. 73-3=70. 70-?=50. ?-?=? fill in the blanks to solve

What is the standard deviation of the data set? 7, 3, 4, 2, 5, 6, 9 Round the answer to the tenths place.

Ainat [17]

The standard deviation would be A. 2.4

3 0

3 years ago

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I think of a number, add 8 to it and the result is 14. Find the number

Leya [2.2K]

Answer:

6

Step-by-step explanation:

The equation for this would be:

n+8=14, since we are adding 8 to a number and getting 14

To solve, isolate the variable n, by subtracting 8 from both sides

n+8=14

n+8-8=14-8

n=6

The number is 6

3 0

2 years ago

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An angle measures 148° more than the measure of its supplementary angle. What is the measure of each angle? AND DONT PLAGERISE!!

Usimov [2.4K]

Answer:

Step-by-step explanation:

Supplementary angles add up to 180°.

“θ is 148° more than its supplement”

Supplement of θ = 180°-θ

θ = (180°-θ) + 148°

2θ = 328°

θ = 164°

Supplement of θ = 180°-164° = 16°

6 0

2 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

3 years ago

Suppose you buy a CD for $500 that earns 3% APR and is compounded quarterly. The CD matures in 3 years. Assume that if funds are

postnew [5]

The question is asking to choose among the following choices that states the early withdrawal fee of the account given in the problem, base on my calculation and further formulation about the said problem, I would say that the answer would be letter D. $3.75. I hope you are satisfied with my answer

5 0

2 years ago

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