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weqwewe [10]
3 years ago
8

How do you solve 9!/5! ?

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

3024.

Step-by-step explanation:

9! / 5!

=  9*8*7*6*5*4*3*2*1

   -------------------------

         5*4*3*2*1

We can cancel out  the 5*4*3*2*1 to give:    

9*8*7*6

=  3024

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What is the product
cricket20 [7]

Answer:

\left[\begin{array}{cc}6&18\\\end{array}\right]

Step-by-step explanation:

To find the product of the matrices: \left[\begin{array}{cc}4&2\\\end{array}\right] × \left[\begin{array}{cc}-2&5\\7&-1\\\end{array}\right]

Multiply rows of the first matrix by the columns of the second matrix.

(4 × (–2) + 2 × 7          4 × 5 + 2 × (–1))

After simplifying this, we get the product \left[\begin{array}{cc}6&18\\\end{array}\right]

Hence, \left[\begin{array}{cc}4&2\\\end{array}\right] × \left[\begin{array}{cc}-2&5\\7&-1\\\end{array}\right] = \left[\begin{array}{cc}6&18\\\end{array}\right]

6 0
2 years ago
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klio [65]

Answer: C

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D is eliminated because of 1 and 6, again 3 plus 2 is 5 not 6

3 0
2 years ago
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Reil [10]

Answer:

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Step-by-step explanation:

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It requires you to make a the subject of the formula

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Dividing both sides by t then

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Therefore, the equivalent for a is a=\frac {f-v}{t}

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Step-by-step explanation:

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