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weqwewe [10]
3 years ago
8

How do you solve 9!/5! ?

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

3024.

Step-by-step explanation:

9! / 5!

=  9*8*7*6*5*4*3*2*1

   -------------------------

         5*4*3*2*1

We can cancel out  the 5*4*3*2*1 to give:    

9*8*7*6

=  3024

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The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
What is the answer to <br>-5+62×(-2)?
ladessa [460]
-129 is the anwser to ur problem
3 0
3 years ago
Read 2 more answers
Bailey is comparing two squares. The first square has an area of 144 cm2, and the second square has an area of 81 cm2. What is t
Nadusha1986 [10]

Answer:

They are both 63 Inches/ Lengths apart.

Step-by-step explanation:

<em>You see when it comes to cm2 inches and lengths You must always Analyze your work and figure out if you can seperate the two among themselves equally. 81 Goes into 144. 63 plus equation.</em>

7 0
2 years ago
fresh+cranberries+have+99%+of+water.+partially+dried+cranberries+have+98%+of+water.+jack+picked+100+pounds+of+cranberries.+how+m
Mnenie [13.5K]

Answer:

  50 lb

Step-by-step explanation:

Before drying, the cranberries have ...

  (100% -99%)(100 lb) = 1 lb

of "meat."

After drying, that represents (100% -98%) = 2% of the total weight. Then the total weight is ...

  1 lb = 2%·x

  x = (1 lb)/0.02 = 50 lb

The dried cranberries will weigh 50 lb.

8 0
2 years ago
Write 4.625 as a mixed number in simplest form
Zarrin [17]
4 625/1,000 to 4 25/40 to 4 5/8
4 0
3 years ago
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