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Mkey [24]
3 years ago
13

How do I solve for x here?

Mathematics
1 answer:
emmasim [6.3K]3 years ago
5 0
(x+108) and (x+88) are supplementary angles. This means that they add to 180.

(x+108) + (x+88) = 180

Solve for x:

2x + 196 = 180

2x = -16

x = -8










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Are the decimals 0.4 and 0.40 equal?
zepelin [54]
0.4 and 0.40 are equal. That zero on the hundredths place does not matter.
3 0
3 years ago
Read 2 more answers
Write an equation and solve for x.
nydimaria [60]

Answer:

120

Step-by-step explanation:

i don't know if you still need help, but the answer is x=180-30-30=120 degrees

7 0
3 years ago
Solve the following System of Equations<br> 5x+4y-z=1<br> 2x-2y+z=1<br> -x-y+z=2
podryga [215]

Answer:

x = 0 , y = 1 , z = 3

Step-by-step explanation:

Solve the following system:

{5 x + 4 y - z = 1 | (equation 1)

2 x - 2 y + z = 1 | (equation 2)

-x - y + z = 2 | (equation 3)

Subtract 2/5 × (equation 1) from equation 2:

{5 x + 4 y - z = 1 | (equation 1)

0 x - (18 y)/5 + (7 z)/5 = 3/5 | (equation 2)

-x - y + z = 2 | (equation 3)

Multiply equation 2 by 5:

{5 x + 4 y - z = 1 | (equation 1)

0 x - 18 y + 7 z = 3 | (equation 2)

-x - y + z = 2 | (equation 3)

Add 1/5 × (equation 1) to equation 3:

{5 x + 4 y - z = 1 | (equation 1)

0 x - 18 y + 7 z = 3 | (equation 2)

0 x - y/5 + (4 z)/5 = 11/5 | (equation 3)

Multiply equation 3 by 5:

{5 x + 4 y - z = 1 | (equation 1)

0 x - 18 y + 7 z = 3 | (equation 2)

0 x - y + 4 z = 11 | (equation 3)

Subtract 1/18 × (equation 2) from equation 3:

{5 x + 4 y - z = 1 | (equation 1)

0 x - 18 y + 7 z = 3 | (equation 2)

0 x+0 y+(65 z)/18 = 65/6 | (equation 3)

Multiply equation 3 by 18/65:

{5 x + 4 y - z = 1 | (equation 1)

0 x - 18 y + 7 z = 3 | (equation 2)

0 x+0 y+z = 3 | (equation 3)

Subtract 7 × (equation 3) from equation 2:

{5 x + 4 y - z = 1 | (equation 1)

0 x - 18 y+0 z = -18 | (equation 2)

0 x+0 y+z = 3 | (equation 3)

Divide equation 2 by -18:

{5 x + 4 y - z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 3 | (equation 3)

Subtract 4 × (equation 2) from equation 1:

{5 x + 0 y - z = -3 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 3 | (equation 3)

Add equation 3 to equation 1:

{5 x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 3 | (equation 3)

Divide equation 1 by 5:

{x+0 y+0 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 3 | (equation 3)

Collect results:

Answer: {x = 0 , y = 1 , z = 3

3 0
4 years ago
a physics student stands at the top of a hill that has an elevation of 56 meters. He throws a rock and it goes up in the air and
babunello [35]
The answer is 57.04 meters. 
Solution:
The height y of the rock above the ground as a function of the horizontal distance x from the starting point on top of the hill can be modeled by the equation 
     y = -0.04x^2 + 1.3x + 56

We now set this equation equal to zero because the height of the ground where the rock will land is zero:
     0 = -0.04x^2 + 1.3x + 56

Since we have a quadratic equation, we can calculate for the horizontal distance x by using the quadratic formula     
     x = [-b ± sqrt(b^2 - 4ac)] / 2a      
     x = {-1.3 ± sqrt[1.3^2 - 4(-0.04)(56)]} / 2(-0.04)     
     x = (-1.3 ± sqrt(10.65)) / (-0.08)     
     x =  -24.54 meters or  57.04 meters
There are two solutions for x but one is negative, so we choose the positive value. 
5 0
3 years ago
Please help me!!!! <br> It is about linear function equations
jolli1 [7]
Y=5x-3; what is:
y=5x+(-3)
3 0
3 years ago
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