The weight of the new student is 27 kg.
Average weight
= total weight ÷total number of students
<h3>
1) Define variables</h3>
Let the total weight of the 35 students be y kg and the weight of the new student be x kg.
<h3>2) Find the total weight of the 35 students</h3>
<u>
</u>
y= 35(45)
y= 1575 kg
<h3>3) Write an expression for average weight of students after the addition of the new student</h3>
New total number of students
= 35 +1
= 36
Total weight
= total weight of 35 students +weight of new students
= y +x

<h3>4) Substitute the value of y</h3>

<h3>5) Solve for x</h3>
36(44.5)= 1575 +x
1602= x +1575
<em>Subtract 1575 from both sides:</em>
x= 1602 -1575
x= 27
Thus, the weight of the new student is 27 kg.
Answer:
0.42* 1265=x
Step-by-step explanation:
There are 1265 students in Cypress Middle School. So we already know one part of the equation. 42% of these students are in PE. So we know that 42% of these 1265 students are in PE. Of these means you probably have to multiply 42% and 1265. 42% = 0.42. So to write an equation we take the 0.42 and 1265 and put it together. Therefore, 0.42 times 1265=x.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
No singular point due to the exponent in the solution
The interval is 
b
NONE
Step-by-step explanation:
From the question we are told that

The generally solution is mathematically represented as

=> 
integrating both sides

=> 
=> 
=> 
Here 
=> 
From the above equation we see that the domain for x has no singular point the interval is

Also there is no transient term in the general solution obtained because as
there no case where 
Answer:
E
Step-by-step explanation:
using the rule of radicals
×
⇔
, hence
=
=
×
×
[
= i]
= 2i
→ E
Answer:
I think 9h
Step-by-step explanation:
Since both variable are the same, you can divide the numbers. 27/3=9. Add back in the variable, and the answer would be 9h. That's how I would solve it at least