Answer: Each adult’s meal costed $15
Step-by-step explanation:
This situation can be modeled by the following equation:
2a + 3c = 42, where a = the cost of an adult’s meal, and c = the cost of a child’s meal
Since we know from the problem that a child’s meal costs $4, we know c:
2a + 3(4) = 42
At this point, we can just solve the resulting equation for a:
2a + 3(4) = 42
= 2a + 12 = 42 (simplify 3(4))
= 2a = 30 (subtract 12 from both sides)
= a = 15 (divide both sides by 2)
So, the cost of each adult’s meal was $15.
More months there are the less ty owes
Answer:
Yes
Step-by-step explanation:
The points will be on the same line if they have the same slope. Calculate the slope of each pair. If the slopes are the same, then they lie on the same line.
The slope is the same.
We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D
Answer:
For less than 7 uniforms.
Step-by-step explanation:
The first company she called charges $70 per uniform.
So, the cost of x uniforms will be $70x.
The second company she called charges $280 plus $30 per uniform.
So, the cost of x uniform will be $(280 + 30x).
Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as
70x < 280 + 30x
⇒ 70x - 30x < 280
⇒ 40x < 280
⇒ x < 7
Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)
