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serg [7]
2 years ago
13

1 Calculate the area of the rectangle. N 11 m 5 1/4 m

Mathematics
1 answer:
antoniya [11.8K]2 years ago
5 0

Answer:

57.75 or 57.8

Step-by-step explanation:

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Laboratory Worksheet
aleksandrvk [35]
Heyyyyyyyyyyy Hii what’s up
3 0
2 years ago
It is expected that 563 quadrillion thermal units of Btu (British thermal units) of energy will be
Evgesh-ka [11]

Answer:

the expected rate of change in consumption is 11.83

Step-by-step explanation:

The computation of the expected rate of change in consumption is shown below:

= (Expected quadrillion thermal units - 2003 quadrillion thermal units) ÷ (difference in years)

= (563 - 421) ÷ (2015 - 2003)

= 142 ÷ 12

= 11.83

hence, the expected rate of change in consumption is 11.83

We simply applied the above formula so that the correct value could come

And, the same is to be considered

3 0
3 years ago
BRAINLIEST, help, thank youu!!
mihalych1998 [28]

Answer: B - 15/40

Step-by-step explanation: You can simplify the answer from

3/8 x 5 = 15/40

Hope this helps ty if you do give brainliest. means alot.

6 0
2 years ago
Read 2 more answers
Does there exist a di↵erentiable function g : [0, 1] R such that g'(x) = f(x) for all x 2 [0, 1]? Justify your answer
agasfer [191]

Answer:

No; Because g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Step-by-step explanation:

Assuming:  the function is f(x)=x^{2} in [0,1]

And rewriting it for the sake of clarity:

Does there exist a differentiable function g : [0, 1] →R such that g'(x) = f(x) for all g(x)=x² ∈ [0, 1]? Justify your answer

1) A function is considered to be differentiable if, and only if  both derivatives (right and left ones) do exist and have the same value. In this case, for the Domain [0,1]:

g'(0)=g'(1)

2) Examining it, the Domain for this set is smaller than the Real Set, since it is [0,1]

The limit to the left

g(x)=x^{2}\\g'(x)=2x\\ g'(0)=2(0) \Rightarrow g'(0)=0

g(x)=x^{2}\\g'(x)=2x\\ g'(1)=2(1) \Rightarrow g'(1)=2

g'(x)=f(x) then g'(0)=f(0) and g'(1)=f(1)

3) Since g'(0) ≠ g'(1), i.e. 0≠2, then this function is not differentiable for g:[0,1]→R

Because this is the same as to calculate the limit from the left and right side, of g(x).

f'(c)=\lim_{x\rightarrow c}\left [\frac{f(b)-f(a)}{b-a} \right ]\\\\g'(0)=\lim_{x\rightarrow 0}\left [\frac{g(b)-g(a)}{b-a} \right ]\\\\g'(1)=\lim_{x\rightarrow 1}\left [\frac{g(b)-g(a)}{b-a} \right ]

This is what the Bilateral Theorem says:

\lim_{x\rightarrow c^{-}}f(x)=L\Leftrightarrow \lim_{x\rightarrow c^{+}}f(x)=L\:and\:\lim_{x\rightarrow c^{-}}f(x)=L

4 0
3 years ago
What is the answer to this question?
SOVA2 [1]

Answer:

the answer is option 3rd

5 0
2 years ago
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