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Angelina_Jolie [31]
4 years ago
8

CICU alls

Mathematics
2 answers:
sergeinik [125]4 years ago
6 0

Answer:

(60,90)

For ed2020

Basile [38]4 years ago
5 0

Answer:

it should be (60,90)

Step-by-step explanation:

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Item 20 You have two loans, for 2 years each. The total interest for the two loans is $138. On the first loan, you pay 7.5% simp
Aliun [14]
Interest on first loan = 800*.075*2 = 120 
<span>so the interest on the second loan </span>
<span>= 138-120 = 18 </span>

<span>using the simple interest formula: </span>
<span>18 = P*.03*2 </span>
<span>P = $300</span>
3 0
3 years ago
Question 7. <br><br>Which graph represents a function? ​
Alexxandr [17]

Left side bottom one

A function is a plot for an equation in 2 variables

4 0
3 years ago
Read 2 more answers
Mai’s kitchen table measures a length of 4 cm by a width of 2.5 cm on the scale drawing.
saveliy_v [14]

Answer:

either 10 or 1.6

Step-by-step explanation:

8 0
3 years ago
Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the
Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}

Now, we calculate the sum

\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\

Therefore, we get

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98

So, the sample standard deviation is 6.98.

3 0
3 years ago
The table shows the time 50 students spent on their homework.
seraphim [82]

Answer: Mean = 52.8 mins

Step-by-step explanation:

We have lapses of 30 minutes, so we can write the average for each, this means that:

0 < t < 30 can be averaged to the middle of the range: 15 min.

Doing this, we have that:

7 students 15 min

27 students 45 min

12 students 75 min

4 students 105 min.

Now we can calculate the mean:

mean = (x1*n1 + x2*n2 + ...)/N

where x1 is the amount of time 1, and n1 is the number of students associated to that time and so on. N is the total number of students

Mean = (7*15min + 27*45min + 12*75min + 4*105min)/(7 + 27 + 12 + 4)

Mean = 52.8 mins

8 0
4 years ago
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