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Marina86 [1]
3 years ago
8

Evaluate: the product of 4 and 7*

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

28

Step-by-step explanation:

4 x 7 = 28

Hope this helps you :)

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Sam and Bethan share £54 in the ratio 5:4 how much dose each get
Agata [3.3K]
Ratio 5:4 
Total shares = 5+4 = 9

then to find for 1 share = 54/9 = 6

So Sam share = 6 x 5 = 30
Bethan share = 6 x 4 = 24

Poof: 30+24 = 54

3 0
3 years ago
What is the solution to –2(8x – 4) < 2x + 5?
Contact [7]

The solution to –2(8x – 4) < 2x + 5 is x > 1/6

<h3>How to solve the inequality?</h3>

The expression is given as:

–2(8x – 4) < 2x + 5

Expand

-16x + 8 < 2x + 5

Evaluate the like terms

-18x < -3

Divide both sides by -18

x > 1/6

Hence, the solution to –2(8x – 4) < 2x + 5 is x > 1/6

Read more about inequalities at:

brainly.com/question/11613554

#SPJ1

4 0
2 years ago
Solve for a<br><br> 5 + 7a = 19
Bess [88]
A = 2 all you gotta do is 7 x 2 which is 14 and add 5 to it which equals 19
8 0
3 years ago
Read 2 more answers
Given a≠±b and a^2−b^2 / a+b =12, find a−b.<br> pls hlep
Readme [11.4K]

Answer:

a - b = 12

Step-by-step explanation:

Given

\frac{a^2-b^2}{a+b} = 12 ← factor the numerator

a² - b² ← is a difference of squares and factors as

a² - b² = (a - b)(a + b)

Thus

\frac{(a-b)(a+b)}{a+b} = 12

Cancel the common factor (a + b) on numerator/ denominator, thus

a - b = 12

7 0
3 years ago
What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL¯¯¯¯¯? Enter your answers in the boxe
labwork [276]

Answer:

J(-2, -1), K(4, -5), L(0, -5)

The midpoint of segment JL is

(-2 + 0)/2, (-1 + (-5))/2) = (-2/2, -6/2) = (-1, -3)

The midpoint is

(-2 + 4)/2, (-1 + (-5))/2) = (2/2, -6/2) = (1, -3)

A: (-1, -3), (1, -3)

Step-by-step explanation:

5 0
4 years ago
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