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timama [110]
3 years ago
13

I’m slow and lazy and yeah sorry just at least help

Mathematics
1 answer:
Anna007 [38]3 years ago
3 0

Answer:

2) x = 6    y = 7      3) x = -5    y= 2

Step-by-step explanation:

2) 10x - 8y = 4

   2(-5x + 3y = -9)

-10x + 6y = -18

 10x - 8y =   4      Add both equations together

         -2y = -14

         y = 7            Divide both sides by -2

10(x) - 8(7) = 4       Plug in 7 for the y to solve for x

10x - 56 = 4  

     + 56 + 56        Add 56 to both sides

10x = 60

x = 6                      Divide both sides by 10

3) Where the two lines intersect, that is the solution to x and y.

The lines intersect at (-5,2). x = -5      y = 2

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Solve for x <br> -2^2(-5x+10)=100
masha68 [24]

Answer:

x=7

Step-by-step explanation:

Hi there!

-2^2(-5x+10)=100

Solve -2^2:

-4(-5x+10)=100

Divide both sides by -4:

\displaystyle \frac{ -4(-5x+10)}{-4}=\frac{100}{-4} \\\\-5x+10=-25

Subtract 10 from both sides:

-5x+10-10=-25-10\\-5x=-35

Divide both sides by -5:

\displaystyle \frac{-5x}{-5} = \frac{-35}{-5} \\\\x=7

Therefore, x = 7.

I hope this helps!

3 0
3 years ago
Max w = 5y1 + 3y2<br> s. a.<br> y1 + y2 ≤ 50<br> 2y1 + 3y2 ≤ 60<br> y1<br> , y2 ≥ 0
CaHeK987 [17]

The maximum value of the objective function is 330

<h3>How to maximize the objective function?</h3>

The given parameters are:

Max w = 5y₁ + 3y₂

Subject to

y₁ + y₂ ≤ 50

2y₁ + 3y₂ ≤ 60

y₁ , y₂ ≥ 0

Start by plotting the graph of the constraints (see attachment)

From the attached graph, we have:

(y₁ , y₂) = (90, -40)

Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂

w = 5 * 90 - 3 * 40

Evaluate

w = 330

Hence, the maximum value of the function is 330

Read more about objective functions at:

brainly.com/question/26036780

#SPJ1

7 0
1 year ago
Consider the equation x^2 = 36. Which of the statements below are true? Select all that apply.
Dmitry [639]

Answer:

x = 6 and x = -6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Prove that PQ + QR + RS + SP = 0 in the given quadrilateral<br>PQRS.​
earnstyle [38]

Answer:

PDRS

Step-by-step explanation:

PQ IS EQUAL TO QR AND QR IS ALSO EQUAL TO RS AND RS IS ALSO EQUAL TO SP

4 0
2 years ago
Read 2 more answers
How many different arrangements of 55 letters can be formed if the first letter must be w or k​ (repeats of letters are​ allowed
defon
If the remaining 4 letters can be anything, you have 2*26^4 = 913,952 possible 5-letter ham radio call signs.
3 0
3 years ago
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