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3 years ago

I’m slow and lazy and yeah sorry just at least help

Mathematics

1 answer:

Anna007 [38]3 years ago

3 0

Answer:

2) x = 6 y = 7 3) x = -5 y= 2

Step-by-step explanation:

2) 10x - 8y = 4

2(-5x + 3y = -9)

-10x + 6y = -18

10x - 8y = 4 Add both equations together

-2y = -14

y = 7 Divide both sides by -2

10(x) - 8(7) = 4 Plug in 7 for the y to solve for x

10x - 56 = 4

+ 56 + 56 Add 56 to both sides

10x = 60

x = 6 Divide both sides by 10

3) Where the two lines intersect, that is the solution to x and y.

The lines intersect at (-5,2). x = -5 y = 2

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You're locked out of your house and the only open window is on the second floor, 34 feet above the ground. You need to

disa [49]

Use the Pythagorean theorem to solve.

Ladder = √(34^2 + 13^2)

= √(1156 + 169)

=√1325

= 36.4 feet

Round your answer as needed.

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3 years ago

Ann's Ride

Juli2301 [7.4K]

Ann went (1) for his distance

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3 years ago

Marcel is performing the first test on his company's new electric car. During the test, the electric car reaches a maximum speed

valentina_108 [34]

Answer:

C. The electric car is not moving at 0 seconds and 12 seconds.

Step-by-step explanation:

Given:

The table given is:

x 0 2 4 6 8 10 12

y 0 45 72 81 72 45 0

From the above table, we observe that the car starts from rest and its speed increases from 0 to 6 seconds, the maximum speed being 81 mph.

After 6 seconds, the speed of the car goes on decreasing till it stops at time equal to 12 seconds.

So, the speed of the car at the start when $x=0$ is 0 mph as it is at rest at that time.

Also, when the time is $x=12\ s$ , the car has come to a stop and thus its speed has reduced to 0 mph again. So, the car is not moving after 12 seconds.

From the above conclusion, we can say that only option C is correct.

The electric car is not moving at 0 seconds and 12 seconds.

3 0

3 years ago

Read 2 more answers

This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.

IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is

$\displaystyle\sum_{n=1}^6\frac1{2^n}$

4 0

3 years ago

a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect

PolarNik [594]

Number of dimes were 81 and number of quarters were 47

Solution:

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that There are 128 coins in all

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

Also given that collection of dimes and quarters is worth $19.85

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

$d \times 0.10 + q \times 0.25 = 19.85$

0.1d + 0.25q = 19.85 -------- eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 128 - q -------- eqn 3

Substitute eqn 3 in eqn 2

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

Thus number of dimes were 81 and number of quarters were 47

4 0

3 years ago