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Levart [38]
3 years ago
10

NEED ASAP Which line is parallel to the line y=4x-2?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

y = 4x + 1

Step-by-step explanation:

Given the equation y = 4x - 2, we need to find the equation parallel to this line. Note that for two equations to be parallel to each other, the must have the same slope

Standard form of an equation is y = mx + b

Compare;

mx = 4x

m = 4

Since the slope of the given equation is 4, the required equation must also have a slope of 4

Since we are not given an option, we can assume any equation with a slope of 4

y = 4x + 1 will be parallel to the given equation since they both have the same slope

<em>Note that the equation can be different so far they have the slope of 4</em>

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A tape diagram. There are 65 students out of 100 students who ride the bus. There are question mark students out of 800 students
SVEN [57.7K]

Answer:

<em>800÷100 = 8</em>

<em>65×8=520</em>

\frac{520}{800}

another way:

<em>100%-65%=35%</em>

<em>35% = 0.35</em>

<em>800×0.35= 280</em>

<em>800-280=</em>520

another way:

<em>65% = 0.65</em>

<em>0.65×800=</em>520

Hope it helped! :)

6 0
2 years ago
Trapezoid ABCD has an area of 525 cm squared. If height AB = 21 cm and BC = 37 cm, what is the measure of AD?​
Annette [7]

Answer:

AD = 13

Step-by-step explanation:

Area of trapezoid ABCD

=  \frac{1}{2} (AB + AD) \times AB \\  \\  525=  \frac{1}{2} (37+ AD) \times21\\  \\  525 \times 2=  (37+ AD) \times21 \\  \\ 1050 = 21 \times 37 + 21AD \\  \\ 1050  = 777+ 21AD \\  \\  21AD  = 1050 - 777 \\  \\ 21AD  = 273 \\  \\ AD  =  \frac{273}{21}  \\  \\ AD  = 13

8 0
3 years ago
What is 37% of 293? Plz help me people this is for tomorrow
stira [4]
108.41 i pretty sure
5 0
3 years ago
Read 2 more answers
What is the scale factor of a model car if the scale is 1 inch=2 feeet
crimeas [40]
1 foot = 12 inches 
1in : 2 feet
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5 0
4 years ago
Read 2 more answers
What are the range and domain?
Goryan [66]

Answer:

domain=0

range=2

Step-by-step explanation:

this might be helpful..

7 0
3 years ago
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