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MaRussiya [10]
3 years ago
14

So i have to do 7/9 times 7/4

Mathematics
1 answer:
melisa1 [442]3 years ago
3 0

Answer:

\frac{49}{36} or 1 13/36

Step-by-step explanation:

7*7=49

9*4=36

But 49/36 is an improper fraction so u have to turn it into a mixed number.

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What is the horizontal distance from the plane’s starting position to its finishing position???? I will mark brainliest
Papessa [141]

Answer:

The answer would be 13.3.

Step-by-step explanation:

Use the Pythagorean theorem to find the other distances in the 5, 3, x triangle and the 7, 3, y triangle and add those two answers together plus 3 to get your answer.

3 0
3 years ago
What is the gcf of 150 and 3
Serhud [2]

Answer:

3 is the answer

hope this helps

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Step-by-step explanation:

8 0
3 years ago
F(x) = x, g(x) = 2x<br> combining functions
Alchen [17]

Answer:

f(x) + g(x) = 3x

Step-by-step explanation:

6 0
3 years ago
Help due today please​
coldgirl [10]
<h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>

We know that, Two angles are said to be complementary, if the sum of their measures is 90°.

<u>According to the Question</u>,

⇒ ∠ABD + ∠DBC = 90°

⇒ (2x + 30)° + (3x + 20)° = 90°

⇒ 2x + 30° + 3x + 20° = 90°

⇒ 5x + 50° = 90°

⇒ 5x = 90° - 50°

⇒ 5x = 40°

⇒ x = 40°/5

⇒ x = 8

<u>So</u>, <u>t</u><u>he measure of each angle will be</u>,

⇒ ∠ABD = (2x + 30)°

= 2 × 8 + 30°

= 16 + 30°

= 46°

⇒ ∠DBC = (3x + 20)°

= 3 × 8 + 30°

= 24 + 30°

<h3> = 54° ▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
6 0
3 years ago
What is the equation of the function that is graphed as line a?
34kurt

to get the equation of any straight line we simply need two points off of it, hmmm let's use the points in the picture below for "a".

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{(-4)}}}\implies \cfrac{-6}{2+4}\implies \cfrac{-6}{6}\implies -1

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-1}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-3=-1(x+4)\implies y-3=-x-4\implies y=-x-1

7 0
2 years ago
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