Question

A crowd of people stood on both sides of the street to view a 4th of July Parade.

Answer 1

Given :

Length of parade , $L = 3\ miles=3\times 5280\ miles = 15840\ miles$ .

Breadth of parade , $B=2\times 15=30\ ft$ .

5 people can fit into a $25\ ft^2$ area.

1 mile = 5280 ft .

To Find :

The size of the crowd.

Solution :

Area of parade ,

$A=15840\times 30\ ft^2\\\\A=475200\ ft^2$

Also , 5 people can fit in $25\ ft^2$ area .

So , number of people fit in A is :

$n = \dfrac{475200\times 5}{25}\\\\n=95040$

Therefore , 95040 can fit in the parade .

Hence , this the required solution .