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3 years ago

Write the equation of a circle with a center at (6, 7) and a diameter of 4.

Mathematics

1 answer:

posledela3 years ago

8 0

Answer:

(x - 6)² + (y - 7)² = 4

Step-by-step explanation:

Equation of circle: (x - h)² + (y - k)² = r²

Given center(h,k) = (6,7)

h = 6

k = 7

Dimeter = 4 --

radius, r = $\frac{4}{2}$ = 2

(x - h)² + (y - k)² = r²

(x - 6)² + (y - 7)² = 2²

(x - 6)² + (y - 7)² = 4

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Can anyone help me??

Tasya [4]

Your in luck! I was just learning these percent things today 'xD but Not in luck at the same time. I will answer the 2 questions that's the most I can do.

1. $17.50 with a 7% sales tax

Answer: 17.50 times .07 equals 1.23

17.50 plus 1.23 equals 18.73

The answer is $18.73

2. 21.95 with a 4.25% sales tax

Answer: 21.95+4.25=26.20

Hope this helps!! :D this took me a while to figure out and used a bit of my time. So I hope the time was worth it! :)

5 0

3 years ago

Find all of the eigenvalues λ of the matrix A. (Hint: Use the method of Example 4.5 of finding the solutions to the equation 0 =

Svetradugi [14.3K]

Answer:

$\lambda=8,\ \lambda=-5$

Step-by-step explanation:

Eigenvalues of a Matrix

Given a matrix A, the eigenvalues of A, called $\lambda$ are scalars who comply with the relation:

$det(A-\lambda I)=0$

Where I is the identity matrix

$I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

The matrix is given as

$A=\left[\begin{array}{cc}3&5\\8&0\end{array}\right]$

Set up the equation to solve

$det\left(\left[\begin{array}{cc}3&5\\8&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda \end{array}\right]\right)=0$

Expanding the determinant

$det\left(\left[\begin{array}{cc}3-\lambda&5\\8&-\lambda\end{array}\right]\right)=0$

$(3-\lambda)(-\lambda)-40=0$

Operating Rearranging

$\lambda^2-3\lambda-40=0$

Factoring

$(\lambda-8)(\lambda+5)=0$

Solving, we have the eigenvalues

$\boxed{\lambda=8,\ \lambda=-5}$

8 0

3 years ago

Find the missing side. Round to the nearest tenth. For all 4 pics

Firlakuza [10]

Answer:

1st pic) 17.8

2nd pic) 16.8

3rd pic) 9.1

4th pic) 13.5

Step-by-step explanation:

1st pic: $cos = \frac{adjacent}{hypothenuse}$

(write equation) Cos 27 (cos 27 = 0.89) = $\frac{x}{20}$

(new equation) 0. 89 = $\frac{x}{20}$

(multiply 20 on both sides) 0.89 x 20 = $\frac{x}{20}$ x 20

(solve) 17.8 = x

2nd pic: $tan = \frac{adjacentx}{hypothenuse}$

(write equation) tan 40 (tan 40 = 0.84) = $\frac{32}{x}$

(new equation) 0.84 = $\frac{32}{x}$

(multiply 32 on both sides) 0.84 x 20 = $\frac{32}{x}$ x 20

(solve) 16.8 = x

3rd pic: $cos = \frac{adjacent}{hypothenuse}$

(write equation) cos 55 (cos 55 = 0.57) = $\frac{16}{x}$

(new equation) 0.57 = $\frac{16}{x}$

(multiply 16 on both sides) 0.57 x 16 = $\frac{16}{x}$ x 16

(solve) 9.1 = x

4th pic: $tan = \frac{adjacentx}{hypothenuse}$

(write eqaution) tan 42 (tan 42 = 0.90) = $\frac{x}{15}$

(new equation) 0.90 = $\frac{x}{15}$

(multiply 15 on both sides) 0.90 x 15 = $\frac{x}{15}$ x 15

(solve) 13.5 = x

4 0

3 years ago

Very easy answer but does any one know what C is

Pavel [41]

Answer: As the number of rides given by the taxi driver increased, the earnings of the taxi driver also increases.

7 0

3 years ago

Read 2 more answers

A sector of a circle has central angle θ=5π/6 and area 15π ft2. Find the radius of this circle.

Natali [406]

5pi/6 r^2 = 15pi

R^2 = 18

R= 3sqrt(3)

6 0

3 years ago