Rewrite x + 1 = 3 in terms of y if x = y^2 + 1.

Mathematics

1 answer:

ExtremeBDS [4]3 years ago

3 0

ANSWER:
(y^2+1)+1=3

Hope it helps u! :)

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Which equation shows a valid step in solving /2x-6+2x+6=0?

AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is $(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

$\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$