Answer:
The surface of the prism is 84m²
Step-by-step explanation:
You have 4 figures here (two the same triangles)
you need to determine the surface of each and then sum it to one. This will be your final surface.
rectangles:
3*6= 18m²
5*6 = 30m²
4*6 = 24m²
triangles:
You need to determine the square of the triangles from the Heron's formula.
Heron's formula states that the area of a triangle whose sides have lengths a, b, and c is
,
where s is the semi-perimeter of the triangle; that is,
.
So the permimeter of the triangle is
2p=4+5+3 = 12m
p = 6m
![S = \sqrt{p*(p-a)*(p-b)*(p-c)} = \sqrt{6*(6-3)*(6-4)*(6-5)} = \sqrt{6*3*2*1} =\sqrt{36} =6[m^{2} ]](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7Bp%2A%28p-a%29%2A%28p-b%29%2A%28p-c%29%7D%20%20%3D%20%5Csqrt%7B6%2A%286-3%29%2A%286-4%29%2A%286-5%29%7D%20%20%3D%20%5Csqrt%7B6%2A3%2A2%2A1%7D%20%3D%5Csqrt%7B36%7D%20%3D6%5Bm%5E%7B2%7D%20%5D)
So the surface of the prism is a total sum of all surfaces:
P = 18m²+30m²+ 24m²+2*6m² = 84m²
Answer:
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Step-by-step explanation:
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Answer:
C. 45 and 141 seconds
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 93 seconds
Standard deviation = 16 seconds
99.7% of running times are approximately between:
By the Empirical rule, within 3 standard deviations of the mean, so between 3 standard deviations below the mean and 3 standard deviations above the mean
3 stnadard deviations below the mean
93 - 3*16 = 45 seconds
3 standard deviations above the mean
93 + 3*16 = 141 seconds
The correct answer is:
C. 45 and 141 seconds
Answer:
Step-by-step explanation:
Whitxh answer are u tryna get?
Answer:
Easiest to pick (0, 0) and (1, 1) probably, then slope is 1.
Step-by-step explanation:
Rise over run for (0, 0) and (1, 1) is rise up 1 and run over 1, so 1/1.
This means slope is 1
