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klasskru [66]
3 years ago
8

Ax-bx+y=z solve for x​

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

\bold{Answer}

\boxed{\bold{x=\frac{z-y}{A-b};\quad \:A\ne \:b}}

\bold{Explanation}

  • \bold{Solve: \ Ax-bx+y=z}

\bold{-------------------}

  • \bold{Subtract \ Y \ From \ Both \ Sides}

\bold{Ax-bx+y-y=z-y}

  • \bold{Simplify}

\bold{Ax-bx=z-y}

  • \bold{Factor \ Ax-bx: \ x\left(A-b\right)}

\bold{x\left(A-b\right)=z-y}

  • \bold{Divide \ Both \ Sides \ By \ A-b;\quad \:A\ne \:b}

\bold{\frac{x\left(A-b\right)}{A-b}=\frac{z}{A-b}-\frac{y}{A-b};\quad \:A\ne \:b}

  • \bold{Simplify}

\bold{\frac{x\left(A-b\right)}{A-b}=\frac{z}{A-b}-\frac{y}{A-b};\quad \:A\ne \:b}

\boxed{\bold{Eclipsed}}

Vladimir [108]3 years ago
6 0

Answer:

This question requires us to change the subject of a formula. This can be achieved by following the order of operations in reverse. First, isolate the terms with our variable of interest, x:

ax - bx = z - y

Then, we take x out as it is being multiplied to both a and b:

x(a - b) = z - y

Dividing (a - b) on both sides, we get:

x = (z - y) / (a - b)

Thus, the answer is x= z-y/a-b

Step-by-step explanation:

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<h3>What is natural logarithm?</h3>

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