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ANEK [815]
3 years ago
14

What is the result of cell division?

Biology
1 answer:
lesya [120]3 years ago
8 0
The result of cell division is the process when one parent cell divides into two or more daughter cells so your answer will be B) Two daughter cells with double the DNA of the parent cell. 
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What is the role of shell-building marine creatures in regulating climate?
Katarina [22]

Answer:

they help to remove carbon dioxide through calcification

Explanation:

The correct answer would be that <u>they help to remove carbon dioxide through calcification</u>

<em>Shell-building marine creatures play important roles in regulating climate because they help to remove carbon dioxide from the environment through the process of calcification.</em>

Carbon dioxide is a major driver of climate change because the gas is among the greenhouse gases that absorb radiation from the sun thereby causing the warming of the planet. The more the carbon dioxide in the atmosphere, the more the amount of heat trapped and the more the increase in the global temperature. An increase in the global temperature causes the general climatic factors to become erratic.

Hence, the removal of carbon dioxide through the process of calcification is important for regulating climate change.

8 0
3 years ago
Read 2 more answers
Which type of leukocyte would increase rapidly during an allergy attack or infection by a parasitic worm?
vodka [1.7K]
Eosinophils, Large brick-red cytoplasmic granules found in response to  <span>allergies caused by parasitic worms.
</span>
6 0
3 years ago
What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent as
ASHA 777 [7]

Answer:

(a) AABBCC × aabbcc->AaBbCc     → 1

(b) AABbCc × AaBbCc->AAbbCC   → 1/32

(c) AaBbCc × AaBbCc->AaBbCc     → 1/8

(d) aaBbCC × AABbcc->AaBbCc    → 1/2

Explanation:

In such cases we calculate the probability of each allelic pair separately.

(a) AABBCC × aabbcc -> AaBbCc  

Aa  Aa   Aa  Aa           Bb  Bb  Bb  Bb         Cc  Cc  Cc  Cc

↓                                   ↓                                ↓  

4/4 = 1                          4/4 = 1                       4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 4 will be Bb so the probability is 4/4 = 1.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc   = 1 x 1 x 1 = 1.                

(b) AABbCc × AaBbCc -> AA bb CC

AA  AA   Aa  Aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

↓                                                        ↓           ↓  

2/4                                                    1/4          1/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be AA so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 1 will be bb so the probability is 1/4.

In case of gene C, out of the 4 probable allelic combinations, 1 will be CC so the probability is 1/4.

So, the total probability of getting AA bb CC = 2/4 x 1/4 x 1/4 = 1/32.

(c) AaBbCc × AaBbCc -> AaBbCc

AA  Aa   Aa  aa           BB  Bb  Bb  bb         CC  Cc  Cc  cc

        ↓                                  ↓                               ↓  

       2/4                               2/4                           2/4

In case of gene A, out of the 4 probable allelic combinations, 2 will be Aa so the probability is 2/4.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 2 will be Cc so the probability is 2/4.

So, the total probability of getting AaBbCc = 2/4 x 2/4 x 2/4 = 1/8.

(d) aaBbCC × AABbcc->AaBbCc

Aa  Aa   Aa  Aa               BB  Bb  Bb  bb          Cc  Cc  Cc  Cc

      ↓                                        ↓                                ↓  

4/4 = 1                                       2/4                          4/4 = 1    

In case of gene A, out of the 4 probable allelic combinations, 4 will be Aa so the probability is 4/4 = 1.

In case of gene B, out of the 4 probable allelic combinations, 2 will be Bb so the probability is 2/4.

In case of gene C, out of the 4 probable allelic combinations, 4 will be Cc so the probability is 4/4 = 1.

So, the total probability of getting AaBbCc = 1 x 2/4 x 1 = 1/2.

5 0
4 years ago
What is the role of myelin in neurons?
Sphinxa [80]
B. speeds up action potentials
5 0
4 years ago
In which part of the color spectrum is the loss of color vision most likely to occur?
marin [14]
Also may decline with age in older adults as a result of the yellowing of the lens of the eye. Decline is most likely to occur in the green blue violet part of the color spectrum. Result is trouble accurately matching closely related colors.
6 0
4 years ago
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