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Alexeev081 [22]
3 years ago
13

A cylinder and a cone have the same base and height. The cylinder can hold about 4,712 mc015-1.jpg of sand. Jared says that the

cone can hold about 1,178 mc015-2.jpg of sand. Which explains whether Jared is correct?
Jared is correct because the volume of the cone is less than the volume of the cylinder. The cone holds mc015-3.jpg less sand than the cylinder.
Jared is correct because the cone and the cylinder have the same base and height so the cone holds mc015-4.jpgof sand.
Jared is not correct because the cone and the cylinder have the same base and height so the cone holds mc015-5.jpg of sand.
Jared is not correct because the volume of the cone cannot be found without knowing the radius of the base and the height of the cone.
Mathematics
2 answers:
Mila [183]3 years ago
8 0

Answer:

C

Step-by-step explanation:

exis [7]3 years ago
6 0
The correct answer is C. So, lets go first to the equations that determine the volume of these solids. For the cylinder, that is simple; pi*r*r*h where r is the radius, h is the height and pi is the constant 3.14. For the cone, it is not easy to derive but one gets that the formula is:\frac{ \pi*r^2*h}{3}.

We notice thus that V_{cyl}=\pi*r^2*h=3V_{cone}. That holds irrespective of their radius or height; we only need to know that the heights and radii of the two objects are the same. Now, we have thus that:
\frac{V_{Cyl}}{V_{Cone} } =1/3.

We can check if this holds for Jared's statement; 1178/4712=0.25=1/4. So, it does not hold and thus Jared's statement is incorrect.
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Answer:

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Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

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=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>

To factor it all together;

<u>13r²(2rs + 4r³ - 3s⁴)</u>

Hope this helps!

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