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Oduvanchick [21]
2 years ago
10

Helppppppppppppppppppppp

Mathematics
2 answers:
katrin2010 [14]2 years ago
8 0

Answer:

E

Step-by-step explanation:

You use subtraction property of equality to get rid of that 4.

Subtract 4 from both sides basically.

You get 2x > 6

Then you divide both sides by 2 to get x > 3

Then you graph it.

So it starts on point 3, and since x is greater than 3, it goes to points greater than 3, so 4, 5, 6, ect. but it never goes below or on 3.

The graph starts on three, as 3.00000000000000001 is a viable solution, but  since it says > instead of the underlined >, it is an open circle like o---->

So it is E.

babymother [125]2 years ago
5 0

Answer: its B

Step-by-step explanation:

because the circle is open and its the greater than sign

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Answer:

I'm not sure but i think it is 5

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Drag a statement or reason to each box to complete this proof.
goblinko [34]

The different statements and reasons to prove that −3(x + 8) = −21 are as detailed below.

<h3>How to utilize properties of Algebra?</h3>

Statement 1; −3(x + 8) = −21

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Statement 2; −3(x + 8)/-3 = −21/-3

Reason 2; Division property of Equality

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find the dimensions of the sports field at the right if the width is at least 60 yards AREA = 240 - 400X SQUARE YARDS
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Answer:

<u>The dimensions of the sports field are 80 yards and 3 - 5x yards</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Width of the sports field = At least 60 yards

Area of the sports field = 240 - 400x square yards

We can conclude the shape of the sports field is rectangular.

2. Find the dimensions of the sports field.

A. We need to find the Greatest Common factor between 240 and 400, this way:

The factors of 240 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240 .

The factors of 400 are: 1, 2, 4, 5, 8, 10, 16, 20, 25, 40, 50, 80, 100, 200, 400 .

Then the greatest common factor is 80.

This GCF is also higher than 60, therefore it's one of the dimensions of the sports field.

Now, we calculate the other side of the sports, this way:

Second dimension of the sports field = (240 - 400x)/80

Second dimension of the sports field = 3 -5x

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p\Rightarrow q

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Answer:

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Given the quadratic function

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