Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that 
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So
You must survey 784 air passengers.
Answer:71.4
Step-by-step explanation:140*51%
The valve of the expression would be 184
Answer:
112%
Step-by-step explanation:
The percentage of its capacity is calculated as
Number of people / Maximum Occupancy × 100%
Number of people = 84 people
Maximum Occupancy = 75 people
Hence:
84 people /75 people × 100
= 1.12 × 100
= 112%
Therefore, the percentage of its capacity that is 84 people is 112 %
