<u>Answer</u>: B. Identify the source of the active connection
<em>Any problem can be fixed only finding of the source of it. We can fix a problem in ‘n’ number of ways but it might again come back if source of it is not identified.</em>
<u>Explanation:</u>
Identify the source of the active connection is the NEXT step the team should take. It is very similar to our human body.
If the infection is coming in the body again and again and gets fixed in the treatment, the reason for come - back will be identified so that it does not <em>lead to unnecessary treatment. </em>
In a similar way, if source are identified then the problem of come-back can be avoided. <em>So option B would be the right choice.</em>
False- python is an example of a high level language. Other high levels are c++, PHP, and Java
Answer: The tools which are required to accomplish each step in the data management process are:
1. Cloud Data Management tools.
2. Master Data Management (MDM) tools.
3. Reference Data Management (RDM) tools.
4. ETL tools.
5. Data visualization and analytics tools
Explanation:
Cloud Data Management tools with the help of various API's are able to connect multiples system with their data to the cloud. examples are amazon cloud, google API cloud.
MDM tools are used for creation and maintenance of reference data. example are Profisee
RDM tools is used with the MDM tools and are use to define the businesss processes over the reference data. Examples are Collibra.
ETL tools helps to load data of an organisation to data warehouses after transformation and testing the data pipeline constituting the data from different databases.
Data visualization analytics tools helps to extract and generate report from the big sets of data which can help an organisation to take business decisions.
Shuffle (A[1..m], B[1..n], C[1..m+n]):
Shuf[0, 0] ← True
for j ← 1 to n
Shuf[0, j] ← Shuf[0, j − 1] ∧ (B[j] = C[j])
for i ← 1 to n
Shuf[i, 0] ← Shuf[i − 1, 0] ∧ (A[i] = B[i])
for j ← 1 to n
Shuf[i, j] ← False
if A[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i − 1, j]
if B[i] = C[i + j]
Shuf[i, j] ← Shuf[i, j] ∨ Shuf[i, j − 1]
return Shuf[m, n]
The algorithm runs in O(mn) time.
