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3 years ago

Lines AB and BC are perpendicular. The dashed rays bisect angles ABD and

Mathematics

1 answer:

andrew-mc [135]3 years ago

4 0

It is 45 because angle ABC is 90 degrees and line D splits each side into two equal parts and half of 90 is 45 degrees

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1 ringtone and $3 equals $4, how much is the ringtone

gavmur [86]

Answer:

Step-by-step explanation:

Let's call the ringtone r. If the ringtone and $3 equals $4, then we can write the equation $4=$3+r. To solve, all you have to do is isolate the r by subtracting 3 on each side.

5 0

3 years ago

The line y = hx - 2 where h > 0 meets the curve 3y² = 9x² - 6x + 1.

I am Lyosha [343]

Answer:

h=6

Step-by-step explanation:

since $y =hx -2$ is an equation for a line which intersects with the curve $3y^2 = 9x^2 - 6x +1$ . The point of intersection, let's say $(x_1,y_1)$ , should satisfy the two equations. As a result, the value of y in the second equation can be replaced with the value of y in the first equation as the following,

$3y^2 = 3(hx-2)^2 = 9x^2 - 6x +1\\3(h^2x^2 -4hx + 4) = 9x^2 - 6x + 1\\3h^2 x^2 -12hx +12 = 9x^2 - 6x +1$

therefore, the latter equation can be rewritten in a quadratic equation form as the following,

$(9 - 3h^2) x^2 + (12h-6)x + (1-12) = (9 - 3h^2) x^2 + (12h-6)x -11$ = 0

if the line is tangent to the curve, it means that the line touches the curve at one point, therefore the discernment of the second order equation will be equal to zero for the famous quadratic equation solution.

$b^2 -4ac =0$

where $a=9-3h^2, b=12h-6$ and $c=-11$ , as a result, the following equations can be deduced,

$(12h-6)^2 - 4*(9-3h^2)*(-11) = (144h^2 -144h +36) - (36 -12h^2)*(-11)=\\(144-(-12)*(-11)h^2 ) -144h +36 -(36*(-11)) =\\12 h^2 -144h +432 =0$

therefore, dividing both sides by 12

$h^2 -12 +36 =0\\(h-6)^2 =0\\h=6$

8 0

2 years ago

you fill up 40 gallon pool putting in 2 gallons water every minute, if someone scoops out 1 gallon every 8 minutes, how long wou

Sav [38]

There's a catch here, and I don't really want to go into full detail. Because of
this catch, I think it would be unusually tough to write a simple equation for this
situation. If you wouldn't mind, let's just list it instead:

After . . water added . . total in pool

7 min . . . 14 gallons . . . 14 gallons
1 more . . 1 gallon . . . . . 15 gallons
7 more . . 14 gallons . . . 29 gallons
1 more . . 1 gallon . . . . . 30 gallons
5 more . . 10 gallons . . . 40 gallons, the pool is full

Add up all the minutes: 21 minutes

5 0

3 years ago

Read 2 more answers

Given:

Ulleksa [173]

Triangle ASA's congruence theorems can be used in this ptoof

6 0

3 years ago

Which of the following is an example of a primary objective of a not-for-profit organization?

navik [9.2K]

Answer:

To provide services constituents