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3 years ago

How do you reflect a point over a line

Mathematics

1 answer:

fgiga [73]3 years ago

8 0

You look at the point on the line where it is placed

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Cost of making x widgets is a quadratic function. Costs 15.5 for 3 widgets. How much for 5 widgets

mamaluj [8]

I believe the answer would be 25.83333 or 25.8 if it needed to be simplified

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3 years ago

If an average car is about 16 feet long, about how many car lengths should you have between you and that car in front of you if

Elden [556K]

Answer: 9 cars.

Step-by-step explanation:

given data:

average length of a car = 16feet

speed of the driver = 100miles/hr

Solution:

First we would need to convert the Speed of the car from miles/hr to Feet/secs.

To do this we know that 1mile/hr = 1.467 feet/secs

= 100m/hr * 1.467

= 146.7Feet/secs.

So now the number of cars between him would be

= 146.7Feet/secs / 16

= 9.17

approximately there should be 9 cars between you.

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4 years ago

Kenneth drove 167.5 miles in 3 7/20 hours. What was his average speed?

worty [1.4K]

167.5 miles/ (3 7/20 hours)= 50 miles/hour.

The correct answer is 50 mph~

6 0

4 years ago

Is the number 526 a multiple of 6?

Allisa [31]

No!!! because 526 is not perfectly divisible by 6

6 0

4 years ago

The coordinates of a quadrilateral are (1,3), (7,-3), (1,-9), and (-5,-3). What shape is formed? Select all that apply. -Kite -R

chubhunter [2.5K]

Answer: Sqaure

Step-by-step explanation:

We obtain the figure by either plotting or finding the distances between the points:

$\begin{aligned}&\text { Distance } b / w \quad A B =\sqrt{(1-7)^{2}+(3-(-3))^{2}}\\&=\sqrt{6^{2}+6^{2}}\\&A B=\sqrt{72} \text { units }\end{aligned}$

$\text { Distance } b / w \quad BC =\sqrt{(7-1)^{2}+(-3-(-9))^{2}} \\BC=\sqrt{72} \text { units }$

$\begin{aligned}\text { Distance } b / w \ C D &=\sqrt{(1-(-5))^{2}+(-9-(-3))^{2}} \\C D=\sqrt{72} \text { units }\end{aligned}$

$$$ Distance $b/w \ A D=\sqrt{(1-(-5))^{2}+(3(-3))^{2}}$A D=\sqrt{72} \text { units }$

Since all the distances of the four sides are equal, we have to check if the shape is either a rhombus or a square by the measuring the length of the diagonals

$\begin{aligned}A C &=\sqrt{(1-1)^{2}+(3-(-9))^{2}} \\&=\sqrt{12^{2}} \\A C &=12 \text { units } \\B D &=\sqrt{(7-(-5))^{2}+(-3-(-3))^{2}} \\&=\sqrt{12^{2}} \\A C &=12 \text { units }\end{aligned}$

The diagonals are also equal; therefore, the figure is a square

7 0

2 years ago