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inna [77]
3 years ago
8

A spherical fish bowl is half-filled with water. The center of the bowl is C, and the length of segment AB is 24 inches, as show

n below. Use Twenty two over seven for pi.
A sphere with diameter 24 inches is drawn.

Which of the following can be used to calculate the volume of water inside the fish bowl?

1 over 24 over 322 over 7(12 3)
1 over 24 over 322 over 7(12 2) (24)
1 over 24 over 322 over 7(24 3)
1 over 24 over 322 over 7(24 2) (12)
Mathematics
2 answers:
antoniya [11.8K]3 years ago
8 0
<span>1 over 24 over 322 over 7(12 3) i think
</span>
zlopas [31]3 years ago
6 0

Answer:

1 over 2 4 over 3 22 over 7 (12^3)

Step-by-step explanation:

Volume of sphere = (4/3)*pi*radius^3  

If the sphere has a diameter of 24 inches, then its radius is 12 inches.

The spherical fish bowl is half-filled; then, the volume of water inside the fish bowl is half of the volume of the bowl, that is,

volume of water = (1/2)*(4/3)*pi*radius^3  

Replacing with radius value and the given value for pi, we get:

volume of water = (1/2)*(4/3)*(22/7)*(12^3)

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Morgarella [4.7K]
Hey there,
It take 45 min to complete 75% of the wall
1% = 45 / 75
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100 % = 0.6 x 100
           = 60 min
It takes her 60 mins or 1 hour to finish building the wall.

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5 0
3 years ago
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Answer:

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Step-by-step explanation:

8 times 7=56

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3 years ago
Which of the following situations represents a proportional
Mamont248 [21]
The answer is that be C.
4 0
3 years ago
How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
Pls fastttttttttttttttt​
Lera25 [3.4K]

a= -1, b= 2 & c= -3

abc= -1 x 2 x -3

= 6

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3 years ago
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