<h2>Question;</h2><h2> 86÷2=1</h2><h2>Answer;</h2><h2>86÷2=43</h2><h2> </h2>
<h2>Hope it helps brainliest and liked my answer please</h2>
Answer:
So about 95 percent of the observations lie between 480 and 520.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
The mean is 500 and the standard deviation is 10.
About 95 percent of the observations lie between what two values?
From the Empirical Rule, this is from 500 - 2*10 = 480 to 500 + 2*10 = 520.
So about 95 percent of the observations lie between 480 and 520.
Answer:
8 and 6
Step-by-step explanation:
Two numbers are such that their difference, their sum, and their product are to
each other as 1:7:24. Their product must equal what number?
:
Two numbers a & b
Let x = the multiplier
:
a - b = 1x
a + b = 7x
a * b = 24x
:
Add the 1st two equations
a - b = x
a + b = 7x
2a = 8x
a = 4x
or
x = .25a
:
a * b = 24x
Replace 24x; a = 4x therefore:
a * b = 6a
b = 6
;
Using the 1st equation
a - b = 1x
Replace b with 6 and x with .25a
a - 6 = .25a
a - .25a = 6
.75a = 6
a =
a = 8
:
Find the multiplier
a - b = x
8 - 6 = 2
:
Check this
a - b = 2 (1*2)
a + b = 14; (7*2)
a * b = 48: (24*2)
:
The numbers are 8 and 6; their products = 48
2/3 hour =2/3×60 min=40 min
2/3 hour=2/3×3600 seconds=2400seconds
There could be problems like there is a light which would flicker in every 7 seconds and there is another one which would flicker in every 8 seconds. So, how many times would they flicker until they would flicker at the same time?
