Answer:
0.289792.
Step-by-step explanation:
If we define a month with one or more accident as "success"; and
A month with no accident as "failure" .
- P(one or more accidents will occur during any given month)=0.60.
- P(no accident will occur during any given month)=1-0.60=0.40
We want to calculate the probability that there will be at least four months in which no accidents occur before the fourth month in which at least one accident occurs.
in this case, let k=number of failures before the fourth success
Therefore, 
k follows a negative binomial distribution.
Therefore, the probability is:
![P(k\geq 4)=1-P(k\leq 3)\\=1-\sum_{k=0}^{3}\left(\begin{array}{ccc}3+k\\k\end{array}\right)(0.60)^4(0.40)^k\\=1-(0.60)^4 \left[\left(\begin{array}{ccc}3\\0\end{array}\right)(0.40)^0+\left(\begin{array}{ccc}4\\1\end{array}\right)(0.40)^1+\left(\begin{array}{ccc}5\\2\end{array}\right)(0.40)^2+\left(\begin{array}{ccc}6\\3\end{array}\right)(0.40)^3\right]\\=1-(0.60)^4 \left[ 1+1.6+1.6+1.28\right]\\=1-(0.60)^4[5.48]\\=0.289792](https://tex.z-dn.net/?f=P%28k%5Cgeq%204%29%3D1-P%28k%5Cleq%203%29%5C%5C%3D1-%5Csum_%7Bk%3D0%7D%5E%7B3%7D%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D3%2Bk%5C%5Ck%5Cend%7Barray%7D%5Cright%29%280.60%29%5E4%280.40%29%5Ek%5C%5C%3D1-%280.60%29%5E4%20%5Cleft%5B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C0%5Cend%7Barray%7D%5Cright%29%280.40%29%5E0%2B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C1%5Cend%7Barray%7D%5Cright%29%280.40%29%5E1%2B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C2%5Cend%7Barray%7D%5Cright%29%280.40%29%5E2%2B%5Cleft%28%5Cbegin%7Barray%7D%7Bccc%7D6%5C%5C3%5Cend%7Barray%7D%5Cright%29%280.40%29%5E3%5Cright%5D%5C%5C%3D1-%280.60%29%5E4%20%5Cleft%5B%201%2B1.6%2B1.6%2B1.28%5Cright%5D%5C%5C%3D1-%280.60%29%5E4%5B5.48%5D%5C%5C%3D0.289792)
The required probability is 0.289792.
The expression which is equivalent to the given expression as in the task content is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.
<h3>What is the expression which is equivalent to the given expression?</h3>
According to the task content, it follows that the expression given is;
(1.5⁵/0.7⁴)³
= 1.5^(3×5) /0.7^(4×3)
= 1.5¹⁵/0.7¹².
Hence, the expression which is equivalent is; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power.
Read more on exponents;
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Answer:
2 horizontal lines are intersected by another line. At the intersection with the first line, the bottom right angle is 91 degrees. At the intersection with the second line, the top right angle is 89 degrees.
Step-by-step explanation:
The last of the statements describes consecutive (same-side) interior angles at the transversal that are supplementary. That condition exists when the lines are parallel.
Answer: -6 3/4
Short explained no step by step
Answer: C, x^2 x y^2 = z^2
Step-by-step explanation:
Pythagorean theorem
