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Usimov [2.4K]
3 years ago
9

How many solutions does have 3x-6=3(x-2)​

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

Answer:

Infinite.

Step-by-step explanation:

3x-6=3\left(x-2\right)

Expand:

3x-6=3x-6

Add 6 to both sides:

3x-6+6=3x-6+6

3x=3x

Subtract 3x from both sides:

3x-3x=3x-3x

0=0

No matter what x is, it doesn't affect the answer. Thus, the equation is true for all values of x.

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Help me please !!!
Nat2105 [25]

Answer:

For 3x^2+4x+4=0

Discriminant= = -32

The solutions are

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= -44

The solutions

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= -36

The solutions

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a= (1-√-1)/3

Step-by-step explanation:

Formula for the discriminant = b²-4ac

let the discriminant be = x for the equations

The solution of the equations

= (-b+√x)/2a and = (-b-√x)/2a

For 3x^2+4x+4=0

Discriminant= 4²-4(3)(4)

Discriminant= 16-48

Discriminant= = -32

The solutions

(-b+√x)/2a =( -4+√-32)/6

(-b+√x)/2a= (-4 +4√-2)/6

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a =( -4-√-32)/6

(-b-√x)/2a= (-4 -4√-2)/6

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= 2²-4(3)(4)

Discriminant= 4-48

Discriminant= -44

The solutions

(-b+√x)/2a =( -2+√-44)/6

(-b+√x)/2a= (-2 +2√-11)/6

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a =( -2-√-44)/6

(-b-√x)/2a= (-2 -2√-11)/6

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= (-6)²-4(9)(2)

Discriminant= 36 -72

Discriminant= -36

The solutions

(-b+√x)/2a =( 6+√-36)/18

(-b+√x)/2a= (6 +6√-1)/18

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a =( 6-√-36)/18

(-b-√x)/2a= (6 -6√-1)/18

(-b-√x)/2a= (1-√-1)/3

6 0
3 years ago
The sum of a number times 7 and 21 is at least 29. Write as an inequality
PtichkaEL [24]

The inequality is 7x + 21 \leq 29

Step-by-step explanation:

<u>DATA:</u>

Let the number be x

Number times 7 = 7*x

Sum of a number times 7 and 21 = 7x + 21

Is at least 29

<u>INEQUALITY:</u>

7x + 21 \leq 29

<u>SOLVE:</u>

7x \leq 29-21

7x \leq 8

x \leq \frac{8}{7}

Therefore, the inequality is 7x + 21 \leq 29

Keyword: Inequality

Learn more about inequality at

  • brainly.com/question/1465430
  • brainly.com/question/1858613

#LearnwithBrainly

6 0
3 years ago
Subtract these polynomials.(4x2 – x + 6) – (x2 + 3) =
kozerog [31]
The answer would be
3x² - x + 3
4 0
3 years ago
Read 2 more answers
Write each fraction as the sum of a whole number and a fraction less than 1
Tpy6a [65]

Given:

The fractions are:

\dfrac{6}{5},\dfrac{11}{7},\dfrac{21}{4}

To find:

The each fraction as the sum of a whole number and a fraction less than 1.

Solution:

The given fraction is \dfrac{6}{5}.

\dfrac{6}{5}=\dfrac{5+1}{5}

\dfrac{6}{5}=\dfrac{5}{5}+\dfrac{1}{5}

\dfrac{6}{5}=1+\dfrac{1}{5}

Therefore, the given fraction \dfrac{6}{5} can be written as 1+\dfrac{1}{5}.

The given fraction is \dfrac{11}{7}.

\dfrac{11}{7}=\dfrac{7+4}{7}

\dfrac{11}{7}=\dfrac{7}{7}+\dfrac{4}{7}

\dfrac{11}{7}=1+\dfrac{4}{7}

Therefore, the given fraction \dfrac{11}{7} can be written as 1+\dfrac{4}{7}.

The given fraction is \dfrac{21}{4}.

\dfrac{21}{4}=\dfrac{20+1}{4}

\dfrac{21}{4}=\dfrac{20}{4}+\dfrac{1}{4}

\dfrac{21}{4}=5+\dfrac{1}{4}

Therefore, the given fraction \dfrac{21}{4} can be written as 5+\dfrac{1}{4}.

7 0
3 years ago
Help me..................... i neeed it
CaHeK987 [17]
Just multiply 38 by 50. 
1,900
7 0
3 years ago
Read 2 more answers
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