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4 years ago

3. Which statement(s) is/are TRUE for all chemical reactions?

Chemistry

1 answer:

kenny6666 [7]4 years ago

3 0

Answer:

the statement is or are true for all chemical reaction is false

Explanation:

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To completely neutralize a 0.325 g sample of pure aspirin, 15.50 mL of a sodium hydroxide solution is added. If 16.25 mL of the

Kruka [31]

<span>a. 0.325 g / 63.55 g/mol = 5.11 X 10^-3 moles Cu. SHould form 5.11 X 10^-3 mol Cu2+

b. Should form 5.11 X 10^-3 mol Cu(OH)2

c. 1 g Zn / 65.4 g/mol = 0.0153 mol Zn
Excess Zn = 0.0153 - 0.0051 = 0.0102 moles excess zinc

d. 5.11 X 10^-3 mol Mg X 24.3 g/mol = 0.124 grams Mg</span>

3 0

3 years ago

Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4

Alinara [238K]

Answer : The balanced equations will be:

(a) $3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $2N_2O_5\rightarrow 2N_2+5O_2$

(c) $2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

Now we have to determine the balanced equations corresponding to the following rate expressions.

(a) $Rate=-\frac{1}{3}\frac{d[CH_4]}{dt}=-\frac{1}{2}\frac{d[H_2O]}{dt}=-\frac{d[CO_2]}{dt}=+\frac{1}{4}\frac{d[CH_3OH]}{dt}$

The balanced equations will be:

$3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH$

(b) $Rate=-\frac{1}{2}\frac{d[N_2O_5]}{dt}=+\frac{1}{2}\frac{d[N_2]}{dt}=+\frac{1}{5}\frac{d[O_2]}{dt}$

The balanced equations will be:

$2N_2O_5\rightarrow 2N_2+5O_2$

(c) $Rate=-\frac{1}{2}\frac{d[H_2]}{dt}=-\frac{1}{2}\frac{d[CO_2]}{dt}=-\frac{d[O_2]}{dt}=+\frac{1}{2}\frac{d[H_2CO_3]}{dt}$

The balanced equations will be:

$2H_2+2CO_2+O_2\rightarrow 2H_2CO_3$

4 0

3 years ago

Which of the following values are not equal to 1 mole?

Gekata [30.6K]

Answer:

none of them are equal to one mole

3 0

3 years ago

Translate the words into formulas, predict the product, & balance the equations. Include states of matter.

Andreyy89

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8 0

3 years ago

when the volume of a gas is changed from 250 mL to 425 mL, the temperture will change from 137 degrees celsius to _____ degrees

FrozenT [24]

Charles law gives the relationship between temperature and volume of gas.
It states that at a constant pressure, volume of gas is directly proportional to the temperature for a fixed amount of gas.
V/T = constant
where V- volume, T- temperature
V1/T1 = V2/T2
Where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
temperature should be in Kelvin for calculation
temperature in K = temperature in Celcius + 273
T1 = 137 °C + 273 = 410 K
substituting values in the equation
250 mL / 410 K = 425 mL /T2
T2 = 697 K
temperature in Celcius = 697 K - 273
temperature = 424 °C

3 0

3 years ago