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3 years ago

if you wanted to study the science of describing, naming, and classifying organisms, what would you study??

Chemistry

1 answer:

crimeas [40]3 years ago

4 0

I think it would be taxonomy which is the the classification of something. Mostly organisms.

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Someone help me please

Artemon [7]

The answer to this problem is 11.6m

3 0

3 years ago

Iteams in house made of thermosetting plastics?

Law Incorporation [45]

Thermoplastics and thermosetting polymers Examples include: polyethylene (PS) and polyvinyl choline (PVC). Common thermoplastics range from 20,000 to 50,000 amu, while thermosets are assumed to have infinite molecular weight.

3 0

3 years ago

NEED ANSWER, ASP! WILL MARK BRAINLIEST!!

Phoenix [80]

Answer:

Answers are below

Explanation:

1. A

2. B

3. A

4. A

5. A

6. B

7. A

8. B

9. B

10. B

11. A, B

12. A

13. A

14. A,B

15. A

16. Not sure

17. Maybe both not sure

18. A

7 0

3 years ago

n unknown metal is either aluminum, iron or lead. If 150. g of this metal at 150.0 °C was placed in a calorimeter that contains

Nitella [24]

Answer : The metal used was iron (the specific heat capacity is $0.449J/g^oC$ ).

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of unknown metal = ?

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_1$ = mass of unknown metal = 150 g

$m_2$ = mass of water = 200 g

$T_f$ = final temperature of water = $34.3^oC$

$T_1$ = initial temperature of unknown metal = $150.0^oC$

$T_2$ = initial temperature of water = $25.0^oC$

Now put all the given values in the above formula, we get

$150g\times c_1\times (34.3-150.0)^oC=-200g\times 4.184J/g^oC\times (34.3-25.0)^oC$

$c_1=0.449J/g^oC$

Form the value of specific heat of unknown metal, we conclude that the metal used in this was iron (Fe).

Therefore, the metal used was iron (the specific heat capacity is $0.449J/g^oC$ ).

6 0

3 years ago

Will fluorine form an anion or a cation? Why?

Serggg [28]

Fluorine will always form an anion. That is because at its basic form, it is electronegative, which means that it attracts electrons who give it a negative charge. This is why it will form an anion.

7 0

3 years ago