First, write the balanced equation:
2KClO3−→−heat2KCl+3O22KClO3→heat2KCl+3O2
Get the MrMr of KClO3KClO3 and KClKCl(122.55 g mol−1122.55 g mol−1 and 74.6 g mol−174.6 g mol−1 respectively)
Next, find out how many moles of KClO3KClO3 are present. From calculations (n=m/Arn=m/Ar), there are 0.463 mol of KClO3KClO3 present.
From the above, we can infer that 2 mol of KClO3KClO3 decompose to give 2 mol of KClKCl. So, by the complete thermal decomposition of 0.463 mol of KClO3KClO3, we get 0.463 mol of KClKCl.
0.463 mol of KClKCl is equal to 34.5 g of KClKCl.
Hence,
34.5 g of KClKCl was produced.
Explanation:
I think it's Al(OH)3 its amphoteric in nature with chemical name Aluminium hydroxide.
hope this helps you
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<u>Answer:</u> The amount of energy released by the reaction is ![3.47\times 10^{14}J](https://tex.z-dn.net/?f=3.47%5Ctimes%2010%5E%7B14%7DJ)
<u>Explanation:</u>
To calculate the energy released, we use Einstein equation, which is:
![E=\Delta mc^2](https://tex.z-dn.net/?f=E%3D%5CDelta%20mc%5E2)
where,
= difference between the masses of products and reactants = 3.86 g = 0.00386 kg (Conversion factor: 1 kg = 1000 g)
c = speed of light = ![3\times 10^8m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8m%2Fs)
Putting values in above equation, we get:
![E=(3.86\times 10^{-3}kg)\times (3\times 10^8m/s)^2](https://tex.z-dn.net/?f=E%3D%283.86%5Ctimes%2010%5E%7B-3%7Dkg%29%5Ctimes%20%283%5Ctimes%2010%5E8m%2Fs%29%5E2)
![E=3.47\times 10^{14}J](https://tex.z-dn.net/?f=E%3D3.47%5Ctimes%2010%5E%7B14%7DJ)
Hence, the amount of energy released by the reaction is ![3.47\times 10^{14}J](https://tex.z-dn.net/?f=3.47%5Ctimes%2010%5E%7B14%7DJ)
Cannot be created, destroyed, or subdivided.
Answer:
3.3 mol HCl
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
120 g HCl
<u>Step 2: Identify Conversions</u>
Molar Mass of HCl - 36.5 g/mol
<u>Step 3: Convert</u>
<u />
= 3.28767 mol HCl
<u>Step 4: Check</u>
<em>We are given 2 sig figs as our lowest. Follow sig fig rules and round.</em>
3.28767 mol HCl ≈ 3.3 mol HCl