The distance from point H to point J is 3 units.The value of n is 3.
Step-by-step explanation:
From the graph, point H is at (n,-6)
Point G location will be at (0,-6)
Point J is at (n,-3)
Observing point H(n,-6) and point J (n,-3) you notice that point J is above point H.find how much far is point H from point J.
d= √(x₂-x₁)²+(y₂-y₁)²
d=√(-3--6)²
d=√3² =√9 = 3
Distance H to J is 3 units
Point G (0,-6) and point H (n,-6) have a distance of 3 units same as point H to J
To get the horizontal length will ;
d=√ (n-0)²
d=√n² but d=3 units
3=√n²
9=n²
√9=n
3=n
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Distance between two points: brainly.com/question/1312275
Key terms : distance, point
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-x+y
Step-by-step explanation:
-1*(x-y)=-x+y
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1
Step-by-step explanation:
