Question

Please solve with working out simultaneous equations 3x+2y=12 2x+2y=10

Answer 1

3x + 2y = 12 ----(i)
2x + 2y = 10 ----(ii)

Subtracting (ii) from (i),

x = 2

Now putting the value of x= 2 in (i),
3 x 2 + 2y = 12
6 + 2y = 12
2y = 6
y = 3

The value of x = 2 , y = 3

Answer 2

Here, 3x + 2y = 12
2x + 2y = 10

Subtract 2nd from 1st equation, 
x = 2

Now, substitute in 2nd, 
2(2) + 2y = 10
2y = 10 - 4
y = 6/2
y = 3

In short, Your Answer would be: (2, 3)

Hope this helps!