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3 years ago

What is the solution or solutions to 3^x=5x

1 answer:

7 0

If the question is as it is now, then there is no solutions.
But I'm guessing that it is 3x^2=5x?
If it is then,

1. Move all terms to one side
3x^2-5x=0

2. Factor out the common term x
x(3x-5)=0

3. Solve for x
x=0 or x=5/3

Have a nice day:D

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Vlad1618 [11]

Answer:

9) 6.3 units

11) n=6√2 and m=12,

10) m=6√3, n=6

12) 330.6 ft

Step-by-step explanation:

1) The Pythagoras Theorem says that, the square of the hypotenuse is the sum of the squares of the two shorter legs.

Let the missing side, which is the hypotenuse be x.

Then

${x}^{2} = {2}^{2} + {6}^{2}$

${x}^{2} = 4 + 36$

${x}^{2} = 40$

$x = \sqrt{40}$

$x = 6.3$

The missing side is 6.3 units to the nearest tenth.

2) This is an isosceles right triangle.

This implies that, the two legs are equal.

$n = 6 \sqrt{2}$

The hypotenuse can be found using Pythagoras Theorem.

${m}^{2} = {(6 \sqrt{2} )}^{2} + {(6 \sqrt{2} )}^{2}$

${m}^{2} = 36(4)$

$m = \sqrt{36 \times 4} = 6 \times 2 = 12$

3) The side lengths of 30°-60°-90° are in the ratio, 2x,x√3,x

From the diagram, the hypotenuse is 12, therefore the other two legs are

$n = \frac{1}{2} (12) = 6$

and

$m = 6 \sqrt{3}$

4) The height of the monument is 115 feet, the hypotenuse is 350.

By Pythagoras Theorem,

${x}^{2} + {115}^{2} = {350}^{2}$

${x}^{2} = {350}^{2} - {115}^{2}$

${x}^{2} = 109275$

$x = \sqrt{109275} = 330.6 ft$

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
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The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

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