Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==>(x-2)(x-1)>=0 positive out of the roots
==> (x<=1 or x>=2) and x>0
==>(0<x<=1) or (x>=2)
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==>(1<=x<=2) and x<0 : no solution
end if
Answer:
The answer is: 
Step-by-step explanation:
we are asked to subtract
from 
so,
.
Hence the desired result is:
.
Answer:
its A.
Step-by-step explanation:
The answer is 4.5 miles. Hope it helps!